Question

List the bonding pairs H and I; S and O; K and Br; Si and Cl, H and F; Se and S; C and H in order of increasing covalent character. 1. (S,O) < (Se,S) < (C,H) = (H,I) = (H,F) < (Si,Cl) < (K,Br) 2. (C,H) = (H,I) = (Se,S) < (K,Br) < (S,O) = (Si,Cl) < (H,F) 3. (K,Br) < (Si,Cl) < (H,F) = (H,I) = (C,H) < (Se,S) < (S,O) 4. (K,Br) < (H,F) < (Si,Cl) < (S,O) < (H,I) = (C,H) < (Se,S) 5. (Se,S) < (C,H) < (H,I) < (S,O) < (Si,Cl) = (H,F) < (K,Br) 6. (H,F) < (Si,Cl) = (S,O) < (K,Br) < (Se,S) = (H,I) = (C,H) 7. None of these

Answer 1

Answer:

1. (S,O) < (Se,S) < (C,H) = (H,I) = (H,F) < (Si,Cl) < (K,Br)

Explanation:

The covalent character always increases down the group, this is because ionic character decreases down the group and also electronegativity.

In the same way, Covalent character always decreases across a period because electronegativity increases across a period.

The higher the electronegativity values between the two atoms, the more ionic it will be.