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myrzilka [38]
2 years ago
12

What evidence supports a conservation law? 6 CO2 → C6H12O6 6 O2 6 CO2 6 H2O light → C6H12O6 6 O2 6 H2O light → C6H12O6 6 O2 6 CO

2 → 3 C6H12O6 3 O2.
Chemistry
1 answer:
docker41 [41]2 years ago
4 0

The law of conservation has been stated that the mass and energy has neither be created nor destroyed in a chemical reaction.

The law of conservation has been evident when there has been an equal number of atoms of each element in the chemical reaction.

<h3>Conservation law</h3><h3 />

The given equation has been assessed as follows:

  • \rm 6\;CO_2\;\rightarrow\;C_6H_1_2O_6

The reactant has absence of hydrogen, while hydrogen has been present in the product. Thus, the reaction will not follow the law of conservation.

  • \rm 6\;O_2\;+\;+\;6\;CO_2\;+\;6\;H_2O\;+\;Light\;\rightarrow\;C_6H_1_2O_6

The number of atoms of each reactant has been different on the product and the reactant side. Thus, the reaction will not follow the law of conservation.

  • \rm 6\;O_2\;+\;6\;H_2O\;+\;Light\;\rightarrow\;C_6H_1_2O_6

The reactant has the presence of carbon, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.

  • \rm 6\;O_2\;+\;6\;CO_2\;\rightarrow\;3\;C_6H_1_2O_6\;+\;3\;O_2

The product has the presence of hydrogen, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.

Learn more about conservation law, here:

brainly.com/question/2175724

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Dmitry [639]

Answer:

it's chemical property

Explanation:

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4 0
2 years ago
Dos moléculas de Clorato de Potasio en estado sólido, al aplicarle calor se descompone en dos moléculas de Cloruro de Potasio en
DedPeter [7]

Answer:

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

Explanation:

Una ecuación de reacción química es una representación simbólica de lo que sucede en un recipiente de reacción.

Al escribir la ecuación de reacción química para una reacción particular, se utilizan los símbolos químicos de todas las especies involucradas.

Por la reacción. en el cual dos moléculas de Clorato de Potasio en estado sólido, al aplicar calor se descompone en dos moléculas de Cloruro de Potasio en estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso, la ecuación de reacción se escribe así;

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

La regla para escribir ecuaciones de reacción química balanceada es que el número de átomos de cada elemento en el lado derecho de la ecuación de reacción debe ser el mismo que el número b de átomos del mismo elemento en el lado izquierdo de la ecuación de reacción.

Si realizamos un conteo de átomos simple en ambos lados de la ecuación de reacción, la regla se cumple

7 0
3 years ago
A package of chocolate instant pudding contains 2640 mg of sodium. how many grams of sodium are in the pudding?
alexgriva [62]

Answer:

2.640

Explanation:

Rounding to the nearest whole number would be 3 if that is needed.

4 0
1 year ago
In the following reaction, which substance is the precipitate? (NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq
mariarad [96]
Assuming that the reactants are:

(NH4)2SO4 (aq) + Ba(NO3)2 (aq)

and the products are:

BaSO4 (s) + 2NH4NO3 (aq),

then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.

According to the solubility rules, the following elements are considered insoluble when paired with SO4:

Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+

Therefore, the precipitate will be BaSO4 (s).

5 0
3 years ago
Read 2 more answers
5. How much heat (in calories) is absorbed by a reaction when
Wewaii [24]

Answer:

1.2 × 10⁴ cal

Explanation:

Given data

  • Mass of water (m): 300 g
  • Initial temperature: 80 °C
  • Final temperature: 40°C

We can calculate the heat released by the water (Q_w) when it cools using the following expression.

Q_w = c \times m \times (T_f - T_i)

where

c is the specific heat capacity of water (1 cal/g.°C)

Q_w = \frac{1cal}{g.\°C}  \times 300g \times (40\°C - 80\°C) = -1.2 \times 10^{4} cal

According to the law of conservation of energy, the sum of the heat released by the water (Q_w) and the heat absorbed by the reaction (Q_r) is zero.

Q_w + Q_r = 0\\Q_r = -Q_w = 1.2 \times 10^{4} cal

7 0
2 years ago
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