2 years ago

Given: triangle ABC and triangle EDC, C is the midpoint of BD and AE. Prove: AB || DE

Mathematics

1 answer:

VladimirAG [237]2 years ago

5 0

Step-by-step explanation:

1. ΔABC=ΔCDE: a) according to the condition BC=CD and AC=CE; b) m∠(BCA)=m∠(DCE).

2. if ΔABC=ΔCDE, then m∠(BAC)=m∠(DEC) and m∠(ABC)=m∠(CDE).

3. if m∠(BAC)=m∠(DEC), then AB || DE (or if m∠(ABC)=m∠(CDE), then AB || DE).

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IceJOKER [234]

Answer:

5/16

Step-by-step explanation:

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2 years ago

mr. cuddy draws a triangle with a perimeter of 36cm. Principal Aranda says that the longest side measures 18 cm, How do you know

hichkok12 [17]

Answer:

See the procedure

Step-by-step explanation:

we know that

The Triangle Inequality Theorem, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

Let

a,b,c the lengths side of triangle

c is the greater side

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P=36 cm

If c=18 cm

then

a+b=18

Applying the Triangle Inequality Theorem

a+b > c

18 > 18 ----> is not true

therefore

Principal Aranda is incorrect

The larger side cannot measure 18 cm

The largest side must be less than 18 cm

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3 years ago

In triangle DEF, CG = (x + 5) units and DG = (3x – 2). What is DG?

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Read 2 more answers

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