A.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\ = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }$

b.
$Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\ \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\= 3 \frac{\sqrt{ 26 }}{ 2 }$

6 0

3 years ago

What is the area of a triangle whose sides are 15 cm, 8 cm and 19 cm?<br>

ludmilkaskok [199]

Is it 2,280
Hope that work

3 0

3 years ago

For the function f(x) = (5-6x)^2, fine f^-1

Scorpion4ik [409]

Answer:

f(-1) = 121

Step-by-step explanation:

f(x) = (5-6x)^2 (First we will substitute x for -1)

f(-1) = (5-6(-1))^2 (Then we will combine like terms)

f(-1) = (11)^2 (Then we will square it)

f(-1) = 121 (You are done)

8 0

3 years ago