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3 years ago

-2 1/4 divided by (-1 1/2)

Mathematics

2 answers:

Gnoma [55]3 years ago

6 0

Answer:

1.5

Step-by-step explanation:

lisabon 2012 [21]3 years ago

3 0

Answer:

1 1/2

Step-by-step explanation:

-2 1/4 = $-\frac{(2*4)+1}{4}= -\frac{9}{4}$

-1 1/2 = $-\frac{(1*2)+1}{2}=-\frac{3}{2}$

-2 1/4 ÷ -1 1/2 = $-\frac{9}{4} * -\frac{2}{3}$

= $\frac{3}{2}$

= 1 1/2

Use KCF method

Keep the first number.

Change division to multiplication

Flip the second number

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7nadin3 [17]

Answer:

Step-by-step explanation:

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2) Multiply 4*3=12 8*7=56

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3 years ago

What is the area of a circle with a radius of 42 in use 3.14 for pi

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3 years ago

Read 2 more answers

In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th

iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095

applying the given data :

a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

= 61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ = 0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

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3 years ago

Ratios equivalent to 16:12

Artyom0805 [142]

Answer:

$\frac{16}{12}$ equivalent to $\frac{ 4}{3}$

Step-by-step explanation:

Given ratio, $\frac{16}{12}$

It can be written as $\frac{16}{12}=\frac{4 \times 4}{4 \times 3}$

cancel common factor,

$\frac{16}{12}=\frac{ 4}{3}$

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4 years ago

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]

matrenka [14]

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

$f(x)=ln(x)$

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

5 0

3 years ago