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3 years ago

What is the exact solution to the system of equations shown on the graph?

Mathematics

2 answers:

ozzi3 years ago

6 0

Answer:

(-1 $\frac{1}{5}$ , 4 $\frac{3}{5}$ )

Step-by-step explanation:

the system of equations is:

y = -3x + 1

y = 2x + 7

anygoal [31]3 years ago

5 0

Answer:

x = 1.2

y = 4.6

(1.2, 4.6)

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nataly862011 [7]

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4 years ago

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skad [1K]

Answer:

The height is 0 when it "drops".

3/2x + 9 = 0

3/2x = -9

3 = -9(2x)

3 = -18x

3/-18x

Change signs, time cant be negative.

x= 6

Another interpretation; Slope is negative it is falling. This interpretation is more accurate.

-3/2x + 9 = 0

-3/2x = -9

-3 = -9(2x)

-3 = -18x

6 = x

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3 years ago

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Stella [2.4K]

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4 years ago

<img src="https://tex.z-dn.net/?f=%20-%2022%20%3D%2011%20-%206a" id="TexFormula1" title=" - 22 = 11 - 6a" alt=" - 22 = 11 - 6a"

jolli1 [7]

<h3>The value of a is equal to 5.5</h3>

-22 = 11 - 6a

Add 6a to both sides.

6a - 22 = 11

Add 22 to both sides.

6a = 33

Divide both sides by 6.

a = 5.5

7 0

3 years ago

Can anyone do 4,5 and 6 for me plz

cricket20 [7]

For question 4, $sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.$

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

$sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.$

Step 2:

Using the above formula, we solve the following values

$sinA = \frac{oppositeside}{hypotenuse}$ $=\frac{a}{c}.$

$cosA = \frac{adjacentside}{hypotenuse}$ $= \frac{b}{c}.$

$tanB= \frac{opposite side}{adjacent side}$ $= \frac{b}{a}.$

$sinJ = \frac{oppositeside}{hypotenuse}$ $= \frac{j}{l}.$

$cosK = \frac{adjacentside}{hypotenuse}$ $= \frac{j}{l}.$

$tanK= \frac{opposite side}{adjacent side}$ $= \frac{k}{j}.$

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

$sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.$

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

$tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277$

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0

3 years ago

What is the exact solution to the system of equations shown on the graph?​

What is the exact solution to the system of equations shown on the graph?