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Daniel [21]
3 years ago
10

When personal information stored digitally on a computer is accidentally

Physics
1 answer:
Schach [20]3 years ago
4 0

Answer:

C. The information is always easily restored."

Explanation:

When the personal information stored digitally on a computer is accidentally

deleted, the data is even stored in the hard disk in various fragments until it is not permanently deleted. Hence the correct option will be "C. The information is always easily restored."

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Find the ratio of the diameter of aluminium to copper wire, if they have the same
kicyunya [14]

Answer:

1.24

Explanation:

The resistivity of copper\rho_1=2.65\times 10^{-8}\ \Omega-m

The resistivity of Aluminum,\rho_2=1.72\times 10^{-8}\ \Omega-m

The wires have same resistance per unit length.

The resistance of a wire is given by :

R=\rho \dfrac{l}{A}\\\\R=\rho \dfrac{l}{\pi (\dfrac{d}{2})^2}\\\\\dfrac{R}{l}=\rho \dfrac{1}{\pi (\dfrac{d}{2})^2}

According to given condition,

\rho_1 \dfrac{1}{\pi (\dfrac{d_1}{2})^2}=\rho_2 \dfrac{1}{\pi (\dfrac{d_2}{2})^2}\\\\\rho_1 \dfrac{1}{{d_1}^2}=\rho_2 \dfrac{1}{{d_2}^2}\\\\(\dfrac{d_2}{d_1})^2=\dfrac{\rho_1}{\rho_2}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{\rho_1}{\rho_2}}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{2.65\times 10^{-8}}{1.72\times 10^{-8}}}\\\\=1.24

So, the required ratio of the diameter of Aluminum to Copper wire is 1.24.

3 0
3 years ago
As a tractor pulls a plow across a field, it exerts a force on the plow in the forward direction. What is the "equal and opposit
Karolina [17]

Answer:

the force of the plow pulling backward on the tractor

Explanation:

7 0
3 years ago
What is the frequency of a wave with a Wavelength of 200 cm?
svetlana [45]

Explanation:

wavelength =200cm=2m

frequency is reciprocal of wavelength

f=1/2

f=0.5Hz or 1/s

5 0
3 years ago
Samantha wants to determine the force she feels in her car as she's going around a corner. What would be some of the assumptions
dalvyx [7]

To determine the Force it is necessary that Samantha starts from the consideration of the dynamic balance between the forces acting on the car. For this, the centripetal force must be equal to the friction force (otherwise the car would lose contact with the ground), the expression of these two forces would be

F_f = F_c

\mu_k mg = \frac{mv^2}{r}

Here,

\mu_k = Coefficient of kinematic friction

m = mass

g = Acceleration due to gravity

v = Velocity

r = Radius

From this relationship then she should assume the following

1) The car travels at a constant speed

2) There is indeed that frictional force between the car and the road

3) There is no loss of mass during displacement

4) The centripetal force must be equal to the frictional force so that the car does not lose contact or slip

5) The radius must be constant

7 0
3 years ago
Two tiny conducting spheres are identical and carry charges of -18.8 µC and +46.5 µC. They are separated by a distance of 2.47 c
sergiy2304 [10]

Answer:

F=-12896N, attractive.

Explanation:

For calculating this force we use the Coulomb Law:

F=\frac{kq_1q_1}{r^2}

Where k=9\times10^9Nm^2/C^{-2} is the Coulomb's constant, q_1 and q_2 the values of each charge and r the distance between them.

Since the Coulomb's constant as I wrote it is in S.I. we have to write all the magnitudes in that system of units, and substitute:

F=\frac{(9\times10^9Nm^2/C^{-2})(-18.8\times10^{-6}C)(46.5\times10^{-6}C)}{(0.0247m)^2}=-12896N

This force is attractive since both charges are of opposite sign.

3 0
3 years ago
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