<span> velocity increases by √3</span>
Answer:
5.3 cm
Explanation:
This question is an illustration of real and apparent distance.
From the question, we have the following given parameters
Real Distance, R = 8.0cm
Refractive Index, μ = 1.5
Required
Determine the apparent distance (A)
The relationship between R, A and μ is:
μ = R/A
i.e.
Refractive Index = Real Distance ÷ Apparent Distance
Substitute values in the above formula
1.5 = 8/A
Multiply both sides by A
1.5 * A = A * 8/A
1.5A = 8
Divide both side by 1.5
1.5A/1.5 = 8/1.5
A = 8/1.5
A = 5.3cm
Hence, the letters would appear at a distance of 5.3cm
Answer:
Well concluding there is no gravity their motions would be slow and lightweighted. Let's say they were playing on Earth it would approximately take around 5 to 6 minutes even less, so in space it will approximately take around 10 to 12 minutes may be more but this is just my opinion after using my calculator! Hope this helped!
Answer:
%
%
Explanation:
From the exercise we know two information. The real speed and the experimental measured by the speedometer
Since the speedometer is only accurate to within 0.1km/h the experimental speed is
Knowing that we can calculate Kinetic energy for the real and experimental speed
Now, the potential error in her calculated kinetic energy is:
%
%
Answer:
3 Volts
Explanation:
Using Ohm's Law
Voltage=current x resistance
V = I x R
V = 1.5 x 2
V = 3 V
