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IrinaVladis [17]

2 years ago

10

A cube with sides of area 18 cm^2 contains a 6.0 nanoCoulomb charge. Find the flux of the electric field through the surface of

the cube in unis of Nm^2/C. Enter a number with one digit behind the decimal point.

1 answer:

Vanyuwa [196]2 years ago

4 0

Answer:

The flux of the electric field is 677.6 Nm²/C

Explanation:

Given that,

Area = 18 cm²

Charge = 6.0 nC

We need to calculate the flux of the electric field

Using Gauss's law

$\phi=\dfrac{q}{\epsilon_{0}}$

Where, q = charge

$\epsilon_{0}$ =permittivity of free space

Put the value into the formula

$\phi=\dfrac{6.0\times10^{-9}}{8.854\times10^{-12}}$

$\phi=677.6\ Nm^2/C$

Hence, The flux of the electric field is 677.6 Nm²/C.

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According to the conservation of momentum law:

<em>"If two objects or bodies are in a closed system and both collide, the total momentum of these two objects before the collision </em> $p_{i}$ <em>will be the same as the total momentum of these same two objects after the collision </em> $p_{f}$ <em>". </em>

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Now, the docking of a space vehicle with the space station is an inelastic collision, which means both objects remain together after the collision.

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Where:

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53.13 °

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At this point we do not need the speed of the first ball after the collision because in that moment is already heading in the direction that we are looking for. Therefore, we just need to use the innitial data to calculate the direction which the first ball will go.

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This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.

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