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IrinaVladis [17]
3 years ago
10

A cube with sides of area 18 cm^2 contains a 6.0 nanoCoulomb charge. Find the flux of the electric field through the surface of

the cube in unis of Nm^2/C. Enter a number with one digit behind the decimal point.
Physics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

The flux of the electric field  is 677.6 Nm²/C

Explanation:

Given that,

Area = 18 cm²

Charge = 6.0 nC

We need to calculate the flux of the electric field

Using Gauss's law

\phi=\dfrac{q}{\epsilon_{0}}

Where, q = charge

\epsilon_{0} =permittivity of free space

Put the value into the formula

\phi=\dfrac{6.0\times10^{-9}}{8.854\times10^{-12}}

\phi=677.6\ Nm^2/C

Hence, The flux of the electric field  is 677.6 Nm²/C.

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