Question

A cube with sides of area 18 cm^2 contains a 6.0 nanoCoulomb charge. Find the flux of the electric field through the surface of the cube in unis of Nm^2/C. Enter a number with one digit behind the decimal point.

Answer 1

Answer:

The flux of the electric field  is 677.6 Nm²/C

Explanation:

Given that,

Area = 18 cm²

Charge = 6.0 nC

We need to calculate the flux of the electric field

Using Gauss's law

$\phi=\dfrac{q}{\epsilon_{0}}$

Where, q = charge

$\epsilon_{0}$ =permittivity of free space

Put the value into the formula

$\phi=\dfrac{6.0\times10^{-9}}{8.854\times10^{-12}}$

$\phi=677.6\ Nm^2/C$

Hence, The flux of the electric field  is 677.6 Nm²/C.