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Yakvenalex [24]
3 years ago
13

13

Chemistry
1 answer:
Reptile [31]3 years ago
4 0

Answer:

Density = 4 g/ml

Explanation:

Given:

Mass = 200 g

Change in Volume = 100 ml - 50 ml = 50 ml

Find:

Density

Computation:

Density = Mass / volume

Density = 200 / 50

Density = 4 g/ml

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Lewis dot diagram for the Cs1+ ion
creativ13 [48]

Answer:

Cs^+

Explanation:

Cesium Lewis dot structure would look like this:

·Cs,  because it only has one valence electron. But, since it has a plus, that means we lost an electron. So, we have to get rid of the dot and you have:

Cs^+

7 0
3 years ago
A 50-mL beaker only has a scale that measures 10, 20, 30, and 40 mL. What is the uncertainty associated with the 50 mL beaker.
Juliette [100K]
If the uncertainty of a certain measurement instrument is not given, then it is assumed to be equal to half of the least count of that instrument. In this case, the least count is 10 ml, so half of this is 5 ml. Therefore, the graduated cylinder has an uncertainty of +/- 5 ml
8 0
3 years ago
What is Tiny grains that contain sperm call
astra-53 [7]

Answer:

Pollen

Explanation:

Pollen is a powdery substance consisting of pollen grains which are male microgametophytes of seed plants, which produce male gametes (sperm cells).

6 0
3 years ago
Hydrogen gas has a density of 0.090 g/L, and at normal pressure and -1.72 C one mole of it takes up 22.4 L. How would you calcul
BlackZzzverrR [31]

Answer:

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Explanation:

Assuming that all caculations are at normal pressure and -1.72°C :

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Where

n is the number of moles of hydrogen

n is the mass of hydrogen

\rho is the density of hydrogen

6 0
3 years ago
Read 2 more answers
If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu
mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

             P1V1/T1 = P2V2/T2

-Solve for V2

             V2 = P1V1T2 / T1P2

2.- Substitution

             V2 = (12)(23)(300) / (200)(14)

3.- Simplification

             V2 = 82800 / 2800

4.- Result

            V2 = 29.6 l

5 0
4 years ago
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