Answer:
![Sum=4*[\frac{n^2-1}{n^2}]](https://tex.z-dn.net/?f=Sum%3D4%2A%5B%5Cfrac%7Bn%5E2-1%7D%7Bn%5E2%7D%5D)
For n=10:
Sum=3.96
For n=100:
Sum=3.9996
For n=1000:
Sum=3.999996
For n= 10000:
Sum=3.99999996
Step-by-step explanation:
Formula:

Rearranging the above formula:
Eq (1)
According to summation formula:

Putt these in Eq (1), and we will get:
![=\frac{12}{n^3}[\frac{n(n+1)(2n+1)}{6}-\frac{n(n+1)}{2}]\\Taking\ n\ as\ common\\=n*\frac{12}{n^3}[\frac{(n+1)(2n+1)}{6}-\frac{(n+1)}{2}] \\=\frac{12}{n^2}*[\frac{(n+1)(2n+1)}{6}]-\frac{12}{n^2}*[\frac{(n+1)}{2}] \\=\frac{2*(n+1)(2n+1)}{n^2}-\frac{6(n+1)}{n^2}\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B12%7D%7Bn%5E3%7D%5B%5Cfrac%7Bn%28n%2B1%29%282n%2B1%29%7D%7B6%7D-%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5C%5CTaking%5C%20n%5C%20as%5C%20common%5C%5C%3Dn%2A%5Cfrac%7B12%7D%7Bn%5E3%7D%5B%5Cfrac%7B%28n%2B1%29%282n%2B1%29%7D%7B6%7D-%5Cfrac%7B%28n%2B1%29%7D%7B2%7D%5D%20%5C%5C%3D%5Cfrac%7B12%7D%7Bn%5E2%7D%2A%5B%5Cfrac%7B%28n%2B1%29%282n%2B1%29%7D%7B6%7D%5D-%5Cfrac%7B12%7D%7Bn%5E2%7D%2A%5B%5Cfrac%7B%28n%2B1%29%7D%7B2%7D%5D%20%5C%5C%3D%5Cfrac%7B2%2A%28n%2B1%29%282n%2B1%29%7D%7Bn%5E2%7D-%5Cfrac%7B6%28n%2B1%29%7D%7Bn%5E2%7D%5C%5C)
Taking
as common:

After more simplifying,
Now ,for n=10:
![Sum=4[\frac{(10^{2})-1}{10^{2}}]\\Sum=3.96](https://tex.z-dn.net/?f=Sum%3D4%5B%5Cfrac%7B%2810%5E%7B2%7D%29-1%7D%7B10%5E%7B2%7D%7D%5D%5C%5CSum%3D3.96)
For n=100:
![Sum=4[\frac{(100^{2})-1}{100^{2}}]\\Sum=3.9996](https://tex.z-dn.net/?f=Sum%3D4%5B%5Cfrac%7B%28100%5E%7B2%7D%29-1%7D%7B100%5E%7B2%7D%7D%5D%5C%5CSum%3D3.9996)
For n=1000
![Sum=4[\frac{(1000^{2})-1}{1000^{2}}]\\Sum=3.999996](https://tex.z-dn.net/?f=Sum%3D4%5B%5Cfrac%7B%281000%5E%7B2%7D%29-1%7D%7B1000%5E%7B2%7D%7D%5D%5C%5CSum%3D3.999996)
For n=10000:
![Sum=4[\frac{(10000^{2})-1}{10000^{2}}]\\Sum=3.99999996](https://tex.z-dn.net/?f=Sum%3D4%5B%5Cfrac%7B%2810000%5E%7B2%7D%29-1%7D%7B10000%5E%7B2%7D%7D%5D%5C%5CSum%3D3.99999996)
Answer:
n = 28°
Step-by-step explanation:
The angle at the centre is twice the angle on the circle subtended on the same arc.
Also angles subtended on the same arc are congruent , thus
m = n
Then
35 + m =
(98 + n ) ← multiply both sides by 2 to clear the fraction
70 + 2m = 98 + n , but since m = n, then
70 + 2m = 98 + m ( subtract m from both sides )
70 + m = 98 ( subtract 70 from both sides )
m = 14 and n = 28
Angle B=118 degrees
angle D=118 degrees
angles C=62 degrees
angle A=62 degrees
angle G=118 degrees
angle K=62 degrees
angle P=62 degrees
angle L=62 degrees
angle N=118 degrees
angle M=118 degrees
angle W=62 degrees
angle I=118 degrees
angle F=62 degrees
angle J=62 degrees
angle E=49 degrees
angle H=118 degrees
angle R=53 degrees
angle U=71 degrees
angle T=109 degrees
angle V=109 degrees
angle S=35.5
angle Q=35.5
Answer:
First one- The ? across from 70 degrees is 70 degrees, and the ones on the side are both 110 degrees.
The second one- The one across 53 degrees is 53 degrees and the ones are the side are both 127 degrees.
Step-by-step explanation:
Take the shown angle and subract that by 180 degrees to get your answer for the missing angles. And the one across from the shown angle is the same number.
Hope this helped im not sure if its right though.
Yes because the larger the bottom number the smaller the amount. :)