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AveGali [126]
3 years ago
15

A truck is carrying 8 cars weighting an average of 4500 pounds each. What is the total weight in tons of the cars on the truck?

Mathematics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

the total weights in tons is 18

Step-by-step explanation:

The computation of the total weights in tons is shown below:

The weight of 8 cars would be

= 4,500 pounds × 8 cars

= 36,000 pounds

Now as we know that 1 ton = 2,000 pounds

So for 8 trucks it would be

= 36,000 pounds ÷ 2,000 pounds

= 18 tons

Hence, the total weights in tons is 18

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Mr. Hayden's Bible class collected $11
ki77a [65]

This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol

Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

Nickel = $0.05

Dime = $0.10

Quarter = $0.25

(n*0.05) + (d*0.10) + (q*0.25)

Solve the equation for q.

q=\frac{1}{2} d

(n*0.05) + (d*0.10) +( \frac{1}{2} d *0.25)

Simplify the expression.

9d + 2n = 440

d - n = -12

Multiply both sides of the equation by -9.

-9d + 9n = 108

9d + 2n = 440

Sum the equations vertically to eliminate at least one variable.

11n = 548

n=\frac{548}{11}

Substitute the given value of n into the equation d - n = -12

d-\frac{548}{11} =-12

d=\frac{416}{11}

Substitute the given value of n into the equation q=\frac{1}{2} d

q=\frac{1}{2} *\frac{416}{11}

q=\frac{208}{11}

Finally

d=\frac{416}{11}        d = 37.818

n=\frac{548}{11}        n = 49.818

q=\frac{208}{11}        q = 18.909

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3 years ago
What is the slope of a line that is perpendicular to the line y = 8x + 5?
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What is the area to this problem?
Nady [450]

Answer:

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Step-by-step explanation:

Each triangle has an area that is ...

... A = 1/2bh = 1/2·7·4

There are 4 such triangles, so the total area is ...

... 4A = 4(1/2)·7·4 = 2·7·4 = 56 . . . . units²

_____

An area formula customarily used when the diagonals are pependicular to each other is that the area is half the product of their lengths.

... A = (1/2)d1·d2 = (1/2)·14·8 = 56

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Step-by-step explanation:

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