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2 years ago

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Find the values of x and y in parallelogram PQRS. PT=y, TR=4x+1, QT=2y, TS=3x+12 In parallelogram PQRS, diagonals PR and QS c

ross at point T. Q P S R T x=nothing and y=nothing

1 answer:

My name is Ann [436]2 years ago

7 0

Here is my answer. I hope this is helpful.

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Explain how to solve 5^(x − 2) = 8 using the change of base formula log base b of y equals log y over log b.

Ray Of Light [21]

Answer:

x = 3.3

Step-by-step explanation:

A equation is given to us and we need to solve out for x. The given equation is ,

Take log on both sides with base as " 10" . We have ,

Simplify using the property of log , , we have ,

Simplify ,

Again simplify using the property of log ,

We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,

Simplify the RHS ,

Add 2 both sides ,

Hence the Value of x is 3.30 .

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2 years ago

Find the missing coordinate to complete the ordered-pair solution to the given linear equation.

ad-work [718]

Y=7x+1

*note that the first number is always the x.
so,

a) (0,?)
y=7(0)+1
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(0,1)

b) (3,?)
y=7(3)+1
y=21+1
y=22
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2 years ago

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How to solve (2.31*10^-6)+(5.87*10^-4)

S_A_V [24]

We want to calculate the following

$2.31\cdot10^{-6}+5.87\cdot10^{-4}$

Using the properties of exponents, we have that

$10^{-6}=10^{-4}\cdot10^{-2}$

So we have

$2.31\cdot10^{-6}+5.87\cdot10^{-4}=2.31\cdot10^{-2}\cdot10^{-4}+5.87\cdot10^{-4}$

So, if factor 10^-4 on the right side, we have

$10^{-4}(2.31\cdot10^{-2}+5.87)$

Note that

$2.31\cdot10^{-2}=0.0231$

Then,

$5.87+2.31\cdot10^{-2}=5.87+0.0231=5.8931^{}$

So we have that

$2.31\cdot10^{-6}+5.87\cdot10^{-4}=5.8931\cdot10^{-4}$

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1 year ago

a die rolled. the set of equally likely outcomes is 1 ,2, 3, 4, 5, 6. find the probability of getting a 10.

Sidana [21]

Answer:

1 in 12

Step-by-step explanation:

hard to explain

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2 years ago

Find the surface area of the pyramid. The side lengths of the base are equal.

Pachacha [2.7K]

Answer:

A = 177.46

Step-by-step explanation:

$A = lw + l\sqrt{(\frac{w}{2})^{2} + h^{2}} + w \sqrt{(\frac{l}{2})^{2} + h^{2}$

A = 6*6+6root((6/2)^2+11.4^2)+6root((6/2)^2+11.4^2)

A = 177.46

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2 years ago

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