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bagirrra123 [75]
3 years ago
12

Classify the following alcohols as primary secondary and tertiary alcohols?​

Chemistry
1 answer:
morpeh [17]3 years ago
4 0
Is this all you need or more ?

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If you set up an experiment with two different independent variables, then the results would be_____.
MariettaO [177]

Answer: A) Inconclusive; you would not know which of the two variables caused the change.

Explanation:

When you set up an experiment, you must make sure that you control the variables such that only one independent variable changes at a time, while all the remainder conditions (the other independent variables) are controlled (fixed).

By observing (measuring) the dependent variable, while only one independent variable changes you can understandhow such independent variable explains (determines) the dependent variable, leading to a conclusion.

Conversely, if two or more independent variables change at a time, then there is no way that you can tell how the output (dependent variable) is related with one or other of the changes of the indipendent variables. You wolud not be able to discriminate (distinguish) the effect of one or other variable, making the experiment inconclusive

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4 0
3 years ago
A common reaction is the formation of butyric acid from butyl alcohol. butyric acid is what causes the odor of rancid butter. ba
Nastasia [14]
Butyl Alcohol on reaction with Oxygen produces Butyric Acid and Water.

The Balance Chemical equation is as follow,

                         C₄H₉OH  +  O₂   →   C₄H₇O₂H  +  H₂O

Result:
          The equation given in statement is already balanced. 

6 0
3 years ago
Read 2 more answers
What is the charge of oxygen in Na2O?
Nuetrik [128]

In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
3 0
2 years ago
Read 2 more answers
Helpppooo give answer thanks
DaniilM [7]

Answer:

625 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 250 mL

Molarity of stock solution (M₁) = 5 M

Molarity of diluted solution (M₂) = 2 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

5 × 250 = 2 × V₂

1250 = 2 × V₂

Divide both side by 2

V₂ = 1250 / 2

V₂ = 625 mL

Therefore, the volume of the diluted solution is 625 mL.

8 0
2 years ago
2c2h6 + 7o2 = 4co2 + 6h2o <br> what mass of co2 will be produced from the reaction of 37.5 g c2h6
ivanzaharov [21]

Answer:

use n=m/M (moles=mass/molar mass) to find out how many moles of C2H6 there are in 60g

Explanation:

8 0
3 years ago
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