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viva [34]
3 years ago
7

HELPP QUICK NO BOTS I WILL REPORT BUT HELP QUICK PLSS What is the slope-intercept equation of the line below?

Mathematics
1 answer:
tester [92]3 years ago
4 0

Answer:

y= -x+2

Step-by-step explanation:

just plug that equation in to see for yourself

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1. A jeepney driver claims that his average monthly income is Php 3000.00 with a standard deviation of Php 300.00. A sample of 3
nydimaria [60]

Answer:

Kindly check explanation

Step-by-step explanation:

The hypothesis :

H0 : μ = 3000

H0 : μ ≠ 3000

The test statistic :

(xbar - μ) ÷ (s/√(n))

xbar = 3500

μ = 3000

σ = 300

n = 30

(3500 - 3000) ÷ (350/√(30))

Test statistic = 7.824

Df = 30 - 1 = 29

Tcritical at 0.01 = 2.462

Test statistic > critical value ; we reject H0 ; and concluded that there is significant evidence that

μ ≠ 3000

7 0
3 years ago
Math question : Please help
MA_775_DIABLO [31]
The answer to the question is C
5 0
3 years ago
75,981 rounded to the nearest ten-thousand
Zinaida [17]

Answer:

80,000

Step-by-step explanation:

7 is the tean thousand

Add 1 because 5 is a big amount.

5 0
3 years ago
If the sum of five consecutive odd integers is 95, what is the smallest of the five integers?
xxMikexx [17]

Answer:

15+ 17+ 19+ 21+23

Step-by-step explanation:

consecutive odd integers, like 1, 3, 5, 7

consecutive even integers, like 2, 4, 6, 8

an integer is a <em><u>whole number</u></em>

4 0
3 years ago
Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

7 0
3 years ago
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