In this problem all the necessary informations are provided. Total capacity of the tank is given as 2560 gallons. It is also given that after 2 weeks or 14 days , only 1944 gallons of water is left. The number of days the whole tank will be empty is required to be found.
Let us assume that the number of days required to empty the tank = x
Then
Now amount of water consumed in 14 days = 2560 - 1944
= 616 gallons
So
616 gallons of water used in = 14 days
2560 gallons of water will be used in = (14/616) * 2560
= 58.18
Then the whole tank will last approximately 58 days if calculated to the nearest whole number.
It looks like this is a square pyramid net, and to find the surface area you need to know the base and height. By looking at the image 5 ft is the height and the base is 3 ft.
The surface area of the square pyramid is <u>40.32</u>
hope this helps!
Answer:
Step-by-step explanation:
Answer:
$1,220,200
Step-by-step explanation:
The total of Mary's payments is ...
$3695.20/mo × 30 yr × 12 mo/yr = $1,330,200
The difference between this repayment amount and the value of her loan is the interest she pays:
$1,330,200 -110,000 = $1,220,200 . . . total interest paid
_____
Mary's effective interest rate is about 40.31% per year--exorbitant by any standard.
Log(2)/log(1.064) ≈ 11.17 . . . . hours
_____
The population can be given by
p(n) = p₀×1.064ⁿ . . . . where n is the number of hours
You want to find n whe p(n) = 2*p₀.
2p₀ = p₀×1.064ⁿ . . . . . . . . . . . . substitute the given information
2 = 1.064ⁿ . . . . . . . . . . . . . . . . . divide by p₀
log(2) = n×log(1.064) . . . . . . . . take logs to make it a linear equation
log(2)/log(1.064) = n . . . . . . . . divide by the coefficient of n
