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dolphi86 [110]
3 years ago
6

If a triangle has angle measures of 114°, 25° and 41°, it can be classified as?

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0
It would be obtuse !
Talja [164]3 years ago
5 0

Answer:

obtuse

Step-by-step explanation:

as one angle is bigger than 90°

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Choose the equations that are equivalent. Select all that apply.
Nadusha1986 [10]

Answer:

A. 52 = 8n +4

C. 4 = 52 - 8n

3 0
3 years ago
Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!
Over [174]

Step-by-step explanation:

initial speed = 272 ft/s

h = -16t² + 272t

a. 1120 = -16t² + 272t we change a bit into

16t² - 272t + 1120 = 0 then divide all with factor 16

t² - 17t + 70 = 0

(t - 10)(t - 7) = 0

t = 10 and t = 7

7 s when it goes up and 10 sec when the rocket goes down.

b. 1152 = -16t² + 272t we change a bit into

16t² - 272t + 1152 = 0 then divide all with factor 16

t² - 17t + 72 = 0

(t - 9)(t - 8) = 0

t = 9 and t = 8 sec

c. since the answer of a and b is:

7 sec and 8 sec the rocket goes up but at 9 sec and 10 sec the rocket goes down then we can take conclusion that the maximum height is reached at 8.5 s

so how long the rocket in the air?

goes up : 8.5 sec

goes down : 8.5 sec

total = 17 sec

8 0
3 years ago
Help is in 1 minute<br> !!!!!!!!!!!!!!!!!!!!!!!!!!
grin007 [14]
The answer to this question is A
6 0
2 years ago
Lance and Alex have 70 pencils. Lance has 4 times as many pencils as Alex. Alex's pencils are shared equally among 2 children. H
gogolik [260]


let l = lance, and a = alex.

so: l + a = 70

and l = 4a

Putting the value for l in the first equation:

4a +a = 70

5a = 70

a = 14.

So Alex has 14 pencils. And Lance has (70-14) 56 pencils.

And if each child gets half of Alex' pencils, then each child will have 7 pencils.

6 0
3 years ago
Use technology to find points and then graph the line y=-5(x-5)+1 following the instructions below.
Svetach [21]

Given:

y=-5(x-5)+1

First, let us find two points from this equation.

We can set values of x and then solve for y.

Let us find the values of y when x = 1, 2, 3, 4, 5

\begin{gathered} y=-5(x-5)+1 \\ y=-5(1-5)+1=21 \\ y=-5(2-5)+1=16 \\ y=-5(3-5)+1=11 \\ y=-5(4-5)+1=6 \\ y=-5(5-5)+1=1 \end{gathered}

We now have a set of points:

(1, 21)

(2, 16)

(3, 11)

(4, 6)

(5, 1)

Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)

The graph would then look like this:

6 0
1 year ago
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