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lana66690 [7]
3 years ago
6

A car's speed changes from 10m/s to 35m/s in 15.0s along a straight road while moving in one way. Find the magnitude of the acce

leration of the car during this period.​
Physics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

1.67 m/s²

Explanation:

Applying,

a = (v-u)/t................ Equation 1

Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

From the question,

Given: v = 35 m/s, u = 10 m/s, t = 15.0 s

Substitute these values into equation 1

a = (35-10)/15

a = 25/15

a = 1.67 m/s²

Hence the acceleration of the car is 1.67 m/s²

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3 years ago
An echo is heard from a cliff 3.71 s after a rifle is fired. How many feet away is the cliff
LenKa [72]

The cliff is 2042 ft away.

We know that the speed of sound in air is directly proportional to the absolute temperature.

First convert the Fahrenheit temperature to Celsius;

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°C = 6.9 °C

Applying the formula;

V1/V2 = √T1/T2

Where; V1 = velocity of sound in air at  0°C

V2 = Velocity of sound in air at 6.9 °C

1087/V2 = √273/279.9

V2= 1101 ft/s

Given that; V = 2s/t

Where s is the distance of the cliff

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s = 1101 ft/s × 3.71 s/2

s = 2042 ft

Learn more:brainly.com/question/15381147

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True or False
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