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lana66690 [7]
3 years ago
6

A car's speed changes from 10m/s to 35m/s in 15.0s along a straight road while moving in one way. Find the magnitude of the acce

leration of the car during this period.​
Physics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

1.67 m/s²

Explanation:

Applying,

a = (v-u)/t................ Equation 1

Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

From the question,

Given: v = 35 m/s, u = 10 m/s, t = 15.0 s

Substitute these values into equation 1

a = (35-10)/15

a = 25/15

a = 1.67 m/s²

Hence the acceleration of the car is 1.67 m/s²

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