Answer:
Radius of the loop is 0.18 m or 18 cm
Explanation:
Given :
Current flowing through the wire, I = 45 A
Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T
Number of turns in circular wire, N = 1
Consider R be the radius of the circular wire.
The magnetic field at the center of the current carrying circular wire is determine by the relation:
Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ Tm/A.
Substitute the suitable values in the above equation.
R = 0.18 m
Answer:
a.) negative charge, positive charge
Explanation:
In order to solve this problem, we will need to see the image that can be seen in the attached image.
The point a has a higher potential than point B of the resistance R as the current flows from a to b.
The positive plate of capacitor b has higher potential than the negative plate c.
Once the capacitor has been charged to the nominal value, it will have the same potential of the battery, its terminals will open interrupting the flow of current. But keeping the potential or voltage differential through its points. This will allow the capacitor to work as a battery while discharging.
