Ways we can reducing Surface Tension

Physics

2 answers:

valina [46]1 year ago

8 0

Surface tension can change with the change in a medium that is just above the layer of the liquid's surface.

Explanation:

Pouring any oil or oily compounds (such as kerosene) on the free surface of the water will reduce the surface tension.

in the atmosphere directly affects the surface tension of the liquid.

If we increase the temperature of the water, then there is a high possibility of the surface tension of the water getting reduced, due to the fact that the net force of attraction is decreased.

Mixing surfactants or emulsifiers into the water will decrease the surface tension.

If the water is subjected to electrification, then the surface tension will be reduced.

masya89 [10]1 year ago

6 0

Answer:

Oil can destroy surface tension in water Adding soap or detergent reduces surface tension in water Increasing the temperature of the liquid reduces surface tension.

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What is the temperature increase of 4.0 kg of water when it is heated by

Nikolay [14]

Answer:

ΔT = 28.667°C is the answer.

Explanation:

Given, Mass of water = 4.0 kg

Water is heated by = 8 × 10² W = 800 W

Time = 10 min = 10 × 60 = 600 s

Now, using the equation of specific heat,

Q = mcΔT

where c is the specific heat capacity of water = 4186 J/kg°C

Q = Pt

Substituting,

Pt = mcΔT

800 × 600 = 4 × 4186 × ΔT

480000 = 16744 × ΔT

ΔT = 28.667

Temperature increased, ΔT = 28.667°C

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Using the formula for work, Match the Force × Distance problems with their correct "Work Performed" answer. The first example ha

Elina [12.6K]

Answer: The answer is in the figure attached.

Explanation:

The Work $W$ done by a Force $F$ refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.

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$1J=(1N)(1m)=Nm$

However, in the British Engineering and Gravitational Systems its unit is Foot-pound (ft-lb). Where $1ft-lb=1.355818J$

Now, when the applied force $F)$ is constant and the direction of the force and the direction of the movement (traveled distance) $d$ are parallel, the equation to calculate it is: