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2 years ago

Ways we can reducing Surface Tension

Physics

2 answers:

valina [46]2 years ago

8 0

Surface tension can change with the change in a medium that is just above the layer of the liquid's surface.

Explanation:

Pouring any oil or oily compounds (such as kerosene) on the free surface of the water will reduce the surface tension.

in the atmosphere directly affects the surface tension of the liquid.

If we increase the temperature of the water, then there is a high possibility of the surface tension of the water getting reduced, due to the fact that the net force of attraction is decreased.

Mixing surfactants or emulsifiers into the water will decrease the surface tension.

If the water is subjected to electrification, then the surface tension will be reduced.

masya89 [10]2 years ago

6 0

Answer:

Oil can destroy surface tension in water Adding soap or detergent reduces surface tension in water Increasing the temperature of the liquid reduces surface tension.

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Answer:

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Explanation:

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3 years ago

Read 2 more answers

The energy flow to the earth from sunlight is about 2 1.4 kW>m . (a) Find the maximum values of the electric and mag- netic f

solmaris [256]

Complete question is;

The energy flow to the earth from sunlight is about 1.4kW/m²

(a) Find the maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity.

(b) The distance from the earth to the sun is about 1.5 × 10^(11) m. Find the total power radiated by the sun.

Answer:

A) E_max ≈ 1026 V/m

B_max = 3.46 × 10^(-6) T

B) P = 3.95 × 10^(26) W

Explanation:

We are given;

Intensity; I = 1.4kW/m² = 1400 W/m²

Formula for maximum value of electric field in relation to intensity is given as;

E_max = √(2I/(ε_o•c))

Where;

ε_o is electric constant = 8.85 × 10^(-12) C²/N.m²

c is speed of light = 3 × 10^(8) m/s

Thus;

E_max = √(2 × 1400)/(8.85 × 10^(-12) × 3 × 10^(8)))

E_max ≈ 1026 V/m

Formula for maximum magnetic field is;

B_max = E_max/c

B_max = 1026/(3 × 10^(8))

B_max = 3.46 × 10^(-6) T

Formula for the total power is;

P = IA

Where;

A is area = 4πr²

We are given;

Radius; r = 1.5 × 10^(11) m

A = 4π × (1.5 × 10^(11))² = 2.82 × 10^(23) m²

P = 1400 × 2.82 × 10^(23)

P = 3.95 × 10^(26) W

5 0

3 years ago

A 10 kg dog runs across the ground and jumps onto an ice-covered pond at 5 m/s. If the force of friction acting on the dog is 8

zzz [600]

Answer:

15.625m

Explanation:

Using the equation of motion

v² = u²+2as

u and v are the initial and final velocities

a is the acceleration

s is the distance

Get the acceleration

According to Newton's second law;

F = ma

8 = 10a

a = 8/10

a = 0.8m/s²

We are also given

v = 5m/s

u = 0m/s

Substitute into the formula above

v² = u²+2as

5² = 0²+2(0.8)s

25 = 1.6s

s = 25/1.6

s = 15.625m

Hence the dog will cover a distance of 15.625m before coming to rest

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3 years ago

A horizontal pipe narrows from a radius of 0.250 m to 0.1000 m. If the speed of the water in the pipe is 1.00 m/s in the larger-

umka21 [38]

Answer:

6.25 m/s

196 kg/s

Explanation:

The areas of the pipe from big to small:

$A = \pi R^2 = \pi*0.25^2 = 0.196 m^2$

$a = \pi r^2 = \pi*0.1^2=0.0314m^2$

As the product of speed and cross-section area is constant, the speed in the smaller pipe would be

$AV = av$

$v = \frac{AV}{a} = \frac{0.196 * 1}{0.0314} = 6.25 m/s$

The mass flow rate would be:

$\dot{m} = \ro AV = 1000 * 0.196 * 1 = 196 kg/s$

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3 years ago

14 km = m on conversions using a ladder method

lozanna [386]

Using the metric units kilometer (km) and meter (m), as seen in the picture of the ladder method example. So, the answer would be 14km = 14000m

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3 years ago

Ways we can reducing Surface Tension​

Ways we can reducing Surface Tension