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Sliva [168]
3 years ago
10

WILL GIVE BRAINLIEST PLEASE I NEED THIS! A 100-kg projectile crashes through a castle wall with a kinetic energy of 266.45 kJ. W

hat was the speed of the projectile?
Physics
1 answer:
denpristay [2]3 years ago
7 0
K.E.=
\frac{1}{2} m {v}^{2}
so just sub in the info you are provided with.
266.45x10^3=0.5×100xv^2
V is 73.
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A racecar driver steps on the gas, and his racecar travels 20 meters in 2 seconds starting from rest. The acceleration of the ra
givi [52]

Answer:

2.5m/s^2

Explanation:

Step one:

given

distance = 20meters

time = 2 seconds

initial velocity u= 0m/s

let us solve for the final velocity

velocity = distance/time

velocity= 20/2

velocity= 10m/s

v^2=u^2+2as\\\\10^2=0^2+2*a*20\\\\100=40a

divide both sides by 40

a= 100/40\\\\a=10/4\\\\a= 5/2\\\\a= 2.5m/s^2

5 0
3 years ago
The reactive force developed by a jet engine to push an airplane forward is called thrust, and the thrust developed by the engin
finlep [7]

The value of the thrust developed by the engine of a boeing 777 in N and Kgf are ;

i) 376616N

ii) 38430Kgf

<h3>What is force?</h3>

Force is a push or a pull. The reactive force always serve to balance the applied force. We are here asked to convert the  the thrust developed by the engine of a boeing 777 which is about 85400 lbf to the following units;

i) N

ii)kgf

Thus;

1 Ib = 0.45 Kg

1 lbf = 0.45 Kg * 9.8 m/s^2 = 4.41 N

We know that;

1 lbf = 4.41 N

85400 lbf = 85400 lbf. * 4.41 N/1 lbf

= 376616N

Again;

1 lbf = 0.45 Kgf

85400 lbf = 85400 lbf * 0.45 Kgf/1 lbf

= 38430Kgf

Learn more about force:brainly.com/question/13191643

#SPJ1

3 0
1 year ago
If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V, the current flowing through the circ
AnnyKZ [126]
The formula for calculating the current flowing in a circuit is:
I = V /R
Where:
I = current = ?
V = voltage = 60 V
R = resistance = 12 Ohms
I = V /R = 60/ 12 = 5
Therefore, the current flowing through the circuit is 5 A.
7 0
3 years ago
Read 2 more answers
Three identical stars of mass M form an equilateral triangle that rotates around the triangle’s center as the stars move in a co
zheka24 [161]

Answer:

v=\sqrt{\dfrac{2GM}{L}}

Explanation:

M = Mass of planets

R = Radius of circle

v = Velocity

\theta = Angle

The circle is inside the triangle

cos\theta=\dfrac{\dfrac{L}{2}}{R}\\\Rightarrow R=\dfrac{L}{2cos\theta}

The centripetal acceleration

\dfrac{Mv^2}{R}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow \dfrac{Mv^2}{\dfrac{L}{2cos\theta}}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow \dfrac{Mv^22cos\theta}{L}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow v^2=\dfrac{2GM}{L}\\\Rightarrow v=\sqrt{\dfrac{2GM}{L}}

The speed of the stars is v=\sqrt{\dfrac{2GM}{L}}

5 0
3 years ago
Find the unbalanced force required to accelerate a 6kg mass at 3ms
Mila [183]

Force (F)=Mass (m)×Acceleration (a).

∴F=ma.

∴F=(2kg)×(3ms2).

∴F=6kgms2=6 Newton. =6N.


5 0
3 years ago
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