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Karo-lina-s [1.5K]
3 years ago
11

In a particular triangle, the second side measures 5 less than twice the first side. The third side measures 3 more than the sec

ond side. In terms of x, what is the perimeter?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
5x-7
If the first side is just x, then the second side must be 2x-5, or 5 less than twice the first. If this is the second side, then the third must be 2x-2, because the third side "measures 3 more than the second side."
The perimeter is 5x-7 = (x) + (2x-5) + (2x-2).
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Answer:

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3 years ago
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
Make a histogram, using a bin width of ten, to display the bowling scores for these 31 players: 87, 104, 79, 94, 117, 82, 72, 11
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Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,  

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data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +  

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3 years ago
A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur
Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

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Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

V=LWH

where

L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in

substitute

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Convert to expanded form

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using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

so

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0
3 years ago
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