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aniked [119]
3 years ago
5

The cost of 4 pretzels is $6.72. What is the cost of each pretzel?

Mathematics
2 answers:
yawa3891 [41]3 years ago
6 0
You will divide 6.72 by 4

\frac{6.72}{4} = 1.68



the cost of each pretzel is $1.68

Not bad!
gayaneshka [121]3 years ago
3 0
Each pretzel costs $1.68
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Brenda is planning her birthday party. She wants to have 10.82 liters of punch, 6.5 gallons of ice cream 3.9 pounds of fudge and
faltersainse [42]

The answer is 0.4328 liters hope this helped!


6 0
2 years ago
1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0
2 years ago
What is the length of 2x+6
matrenka [14]

Answer:   3 i hope this is right

Step-by-step explanation:

8 0
3 years ago
What is 2/15 divided by 4/15
Yanka [14]
The answer is 1/2 or 0.5
4 0
3 years ago
Read 2 more answers
Really struggling! Will give 20 points to answers correctly
Rom4ik [11]

Answer:

8,820

Step-by-step explanation:

One candle:

½ × 10 × 7 × 6

= 210 cm³

42 candles:

42 × 210

= 8,820 cm³

8 0
3 years ago
Read 2 more answers
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