Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
(gof)(0) cannot be evaluated
<em><u>Solution:</u></em>
Given that,
A composite function is denoted by (g o f) (x) = g (f(x)).
The notation g o f is read as “g of f”
Therefore, let us find whether (gof)(0) can be evaluated or not
To find (gof)(0):
(g o f) (x) = g (f(x))
Now substitute the given value of f(x)
Now to find (gof)(0), substitute x = 0
Since 1 divided by 0 is undefined, because any number divided by 0 is undefined
(gof)(0) cannot be evaluated
Answer:
V( 3, -8 )
Step-by-step explanation:
Parable equation is of the form:
( x - h )² = 4p*(y - k)
In that expression, vertex has coordinates V ( h, k )
Then all we have to do is transform the given equation
y = x² - 6x + 1 or x² - 6x = y - 1 (1)
We can get a perfect square trinomial in the first member of the equation according to:
x² - 6x = ( x - 3 )² - 9
(x - 3 )² = x² - 6x + 9
By substitution en equation (1)
( x - 3 )² - 9 = y - 1
( x - 3 )² = y -1 + 9
( x - 3 )² = y + 8
( x - 3 )² = (y + 8 )
Then vertex coordinates are
V( 3 , -8)
Answer:
The margin of error is given below:
Where:
Therefore, the option E = z*6% is correct as it closest to the given answer
