1 because there’s more absorption meaning less water to runoff
Answer:
The correct answer is - 6.8950.61 gm per mole
Explanation:
Given:
One form of hemoglobin is 0.324% Fe by mass
1 hemoglobin = 4 Fe
Solution:
Molar Mass of iron = 55.85
mass of 4 iron atom = 55.85 * 4 = 223.4 gms
0.324 % correspond to 223.4 gms
100 % correspond to = 223.4 *100/0.324
= 68950.61 gm
MM of haemoglobin = 68950.61 gms = 6.8 E4 gms
Scar tissue is made of a protein called collagen
Answer:
Anabolism builds molecules required for the body's functionality. The process of catabolism releases energy. Anabolic processes require energy. ... Examples of catabolic processes are proteins becoming amino acids, glycogen breaking down into glucose and triglycerides breaking up into fatty acids.
Answer:
The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:
p + q = 1
r-6 + R = 1
0.2 + 0.8 = 1
Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64
The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04
And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32
