The smaller of 2 consecutive integers is -15. The equation to determine the consecutive integers is x + (x + 1) = -29
<u>Solution:</u>
Given that sum of two consecutive integer is -29.
Need to write the equation and determine the smaller of 2 consecutive integers.
Let’s smaller integer be represented by variable x
So bigger consecutive integer will be represented by x + 1
As sum of two integer = -29
=> x + (x + 1) = -29
=> 2x + 1 = -29
=> 2x + 30 = 0 ----------(1)
On solving equation (1) for x we get
2x =-30
=> x = -15
Smallest integer = x = -15
Bigger integer = x + 1 = -15 + 1 = -14
Hence required smaller integer = -15 and required equation is x + (x + 1) = -29
Answer:
you didnt give any numbers but, I'm guessing they would pay as much as how big the slices were or if they were a third or a fourth of a slice
When given a literal equation, you will often be asked to solve the equation for a given variable. The goal is to isolate that given variable. The process is the same process that you use to solve linear equations; the only difference is that you will be working with a lot more letters, and you may not be able to simplify as much as you can with linear equations.
2: x = -5/3 ; y = -4/3 (-5/3, -4/3)
Answer:
> Using the remainder theorem, set x + 4 to be equal to 0, i.e.
Step-by-step explanation:
> Using the remainder theorem, set x + 4 to be equal to 0, i.e.
x + 4 = 0
x = - 4
=> Substitute - 4 for x in 3x² - x - 2, i.e.
3(- 4)² - (- 4) - 2
= 3 * 16 + 4 - 2
= 48 + 4 - 2
= 52 - 2
= 50 ...
-4|----3----(-1)----(-2)
-------------(-12)------52
________________
------3------(-13)----50
