The balanced equation for the neutralisation reaction is as follows 2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O stoichiometry of H₃PO₄ to H₂O is 2:6 number of H₃PO₄ moles reacted - 0.24 mol if 2 mol of H₃PO₄ form 6 mol of H₂O then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O therefore 0.72 mol of H₂O are formed
