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3 years ago

What was Johann Dobereiner’s contribution to the development of the periodic table?

Chemistry

2 answers:

Novay_Z [31]3 years ago

5 0

He identified triads of elements that had similar properties

umka21 [38]3 years ago

3 0

<span>he introduced his law of triads. each triad was a group of three elements</span>

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What is the mass in grams of 6.022 x 1023 molecules of CO2?

Kamila [148]

Answer: Molar mass of CO2 is 44 gram/mol. So,the mass of 1 mole or 6.02*10^23 molecules of CO2 is 44 grams

Explanation:

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3 years ago

Which step will decrease the pressure of a gas inside a closed cubical container?

ANTONII [103]

Answer:lol

Explanation:

7 0

3 years ago

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Questions 3,4,5<br> Brainlist

Diano4ka-milaya [45]

Answer:

3. 126.02 g of H₂S and 1109.2 g of NaI

4. 364.5g of Mg

5. 361.08 g of MgSO₄ and 108 g of H₂O

Explanation:

3. This is the reaction

2HI + Na₂S → H₂S + 2NaI

7.4 moles of HI react, so, ratio is 2:1 with H₂S and 2:2 with NaI

We would produce the same moles of NaI, 7.4 moles and the half of moles, of H₂S (7.4 /2) = 3.7 moles

Let's convert the moles to mass (mol . molar mass)

3.7 mol H₂S . 34.06 g/mol = 126.02 g

7.4 mol NaI . 149.9 g/mol = 1109.2 g

4. The balanced reaction is this:

3Mg + N₂ → Mg₃N₂

Ratio is 1:3. Therefore 1 mol of Mg₃N₂ were produced by 3 moles of Mg.

So, 5 moles of Mg₃N₂ would have been produced by 15 moles of Mg. (5 .3)

Let's convert the moles to mass (moles . molar mass)

15 mol . 24.30 g/mol = 364.5 g

5. The reaction is: H₂SO₄ + Mg(OH)₂ → MgSO₄ + 2H₂O

Ratios are 1:1 and 1:2, between sulfuric acid and the products.

If I have 3 moles of acid, I would produce 3 moles of magnessium sulfate and 6 moles of water (3 .2)

Let's convert the moles to mass

3 mol . 120.36 g/mol = 361.08 g of MgSO₄

6 mol . 18 g/mol = 108 g of H₂O

8 0

4 years ago

1: Write balanced complete ionic equation for

monitta

Answer 1 : The balanced complete ionic equation will be,

$NaOH(aq)+HNO_3(aq)\rightarrow H_2O(l)+NaNO_3(aq)$

$Na^+(aq)+OH^-(aq)+H^+(aq)+NO_3^-(aq)\rightarrow H_2O(l)+Na^+(aq)+NO_3^-(aq)$

By removing the spectator ion in this equation, we get the balanced ionic equation.

$OH^-(aq)+H^+(aq)\rightarrow H_2O(l)$

Answer 2 : The balanced net ionic equation will be,

$2Na_3PO_4(aq)+3NiCl_2(aq)\rightarrow Ni_3(PO_4)_2(s)+6NaCl(aq)$

$6Na^+(aq)+2PO_4^{3-}(aq)+3Ni^+(aq)+6Cl^-(aq)\rightarrow Ni_3(PO_4)_2(s)+6Na^+(aq)+6Cl^-(aq)$

By removing the spectator ion in this equation, we get the balanced ionic equation.

$2PO_4^{3-}(aq)+3Ni^+(aq)\rightarrow Ni_3(PO_4)_2(s)$

Answer 3 : The balanced net ionic equation will be,

$2Na_3PO_4(aq)+3NiCl_2(aq)\rightarrow Ni_3(PO_4)_2(s)+6NaCl(aq)$

$6Na^+(aq)+2PO_4^{3-}(aq)+3Ni^+(aq)+6Cl^-(aq)\rightarrow Ni_3(PO_4)_2(s)+6Na^+(aq)+6Cl^-(aq)$

By removing the spectator ion in this equation, we get the balanced ionic equation.

$2PO_4^{3-}(aq)+3Ni^+(aq)\rightarrow Ni_3(PO_4)_2(s)$

Balanced equations : Balanced equations are the equations in which the number of individual elements present on the reactant side must be equal to the number of individual elements present on the product side.

Spectator ions : It is defined as the ions which do not participate in the chemical reaction. These ions exists in the same form on both the sides of the reaction.

7 0

3 years ago

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An acid

Leokris [45]

OPTION D IS YOUR ANSWER.............

6 0

3 years ago