Food consumption affects the rate of alcohol absorption in the bloodstream.
Explanation:
The type of food and therefore the amount<span> of food that </span>is a gift<span> in your </span>epithelial duct once you<span> consume alcohol have </span>the foremost<span> direct </span>impact<span> on </span>the speed<span> of alcohol absorption.</span>
<span>When you consume alcohol on </span>the associate<span> empty </span>abdomen<span>, the alcohol </span>is sometimes<span> absorbed </span>within the<span> blood </span>among<span> fifteen minutes to two-and-a-half hours. If </span>you have got<span> a moderate </span>quantity<span> of food in your </span>abdomen once you<span> drink, that speed slows </span>all the way down to<span> thirty minutes </span>to a few<span> hours. If you’re drinking on a full </span>abdomen<span>, alcohol absorption ranges from </span>3 to 6<span> hours.</span>
Explanation:
An equation that consists of same number of atoms on both reactant and product side is known as a balanced chemical equation.
For example, 
Number of atoms on reactant side are as follows.
C = 7
H = 6
O = 3
Number of atoms on product side are as follows.
C = 1
H = 2
O = 3
Therefore, to balance this chemical equation we multiply
by 8 on reactant side. Whereas we multiply
by 7 and
by 3 on product side.
Therefore, the balanced chemical equation will be as follows.

It's in the periodic table.
See the attached picture. The number below 'Zn' is the molar mass. The closest answer choice is 65.38
An ion is a charged atom or molecule. It is charged because the number of electrons do not equal the number of protons in the atom or molecule. An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom. An example is Iron (III) , Iron (II) , lithium, and hydrogen.
Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
Explanation:
Given:
= 237 K,
= 101.33 kPa,
= ?
= 300 K,
= 151.99 kPa,
= 0.50 L
Formula used is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.