The molarity of the Ca(OH)2 solution is calculated as follows
find the concentration of HCl used from the Ph
that is PH = - log H+= 1.3
H+ = 10^-1.3 = 0.05 M
the moles of HCl = molarity x volume/1000
= 0.05 x 300/1000=0.015 moles
write the reaction equation
that is Ca(OH)2 +2HCl=CaCl2 + 2H20
by use of reacting ratio between Ca(OH)2 to HCl (1:2) the moles of Ca(OH)2 is = 0.015 x1/2=7.5 x10^-3 moles
molarity is therefore = moles /volume in liters
= {( 7.5x10^-3) /50} x1000 = 0.15 M ( answer 5)
Answer:
is equal to the action force , but acts in the opposite direction.
Explanation:
- All you need to solve is apply Newton's third law.
It states that
- Every action has an equal and opposite reaction
Or
The answer is C. Here is the work:
<span>Moles=molarity * volume
2.5 * 0.5 = 1.25mols of NaCI
Mm of NaCI= 58.442468/mol
Multiply the moles by the Mm and you get the grams
1.25 * 58.442468 =73.1g
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KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol
HNO3= 1 mol KOH (keep in mind this because it will be used later).
We also know that 0.100 M KOH aqueous
solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the
definition of molarity).
First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/
1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.
Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.
The final answer is </span>(2) 20.0 mL.<span>
Also, this problem can also be done by using
dimensional analysis.
Hope this would help~
</span>
Answer:
Explanation:
Because unlike ionic bonds (metal and a non-metal) where electrons are "stolen", covalent bonds are defined by the sharing of electrons between non-metals.