Answer:
<h3>The answer is 0.1 mol</h3>
Explanation:
To find out the number of moles we use the formula
where
n is the number of moles
M is the molar mass
m is the mass of the substance
From the question
m = 400 g
M of Ca = 40 g/mol
We have
We have the final answer as
<h3>0.1 mol</h3>
Hope this helps you
Answer:
(1) <em>C</em> C3H7OH = 9.200 M
(2) <em>C</em> C3H7OH = 11.647 m
Explanation:
mixture:
∴ 70% = (g C3H7OH/g mix)×100
∴ 30% = (gH2O/g mix)×100
∴ δ mix = 0.79 g/mL
assuming:
⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix
⇒ g C3H7OH = 70g
⇒ g H2O = 30g
∴ Mw C3H7OH = 60.1 g/mol
∴ Mw H2O = 18 g/mol
(1) Molar concentration (M):
⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M
(2) molal concentration (m):
⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m
Answer: low pH
Hydronium is H^+ and acids give hydronium ions to water solution.
PH = -log H^+ concentration. The higher the concentration, the lower pH value
Answer:
The answer to your question is: density = 5 g/cm³
Explanation:
Data
Volume = v = 2 m³
mass = m = 1 x 10⁴ kg
Density = d = ? g/cm³
Formula
density = mass/volume
Volume
1 m³ ------------------- 1 000 000 cm³
2 m³ ------------------ x
x = (2 x 1 000 000) / 1
x = 2 000 000 cm³
Mass
1 kg ------------------ 1000 g
1 x 10⁴ kg ------------ x
x = (1 x 10⁴ x 1000) / 1
x = 10 000 000 g
density = (10 000 000) / 2 000 000
density = 5 g/cm³
