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3 years ago

CHEM HELP PLEASE

Chemistry

1 answer:

natka813 [3]3 years ago

3 0

Answer:

90.2%

Explanation:

% yield = actual yield/ theoretical yield * 100%

% yield = (312/346)*100% = 90.2%

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The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure

Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate $\Delta H_{vap}$ of the reaction, we use clausius claypron equation, which is:

$\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$P_1$ = vapor pressure at temperature $T_1$

$P_2$ = vapor pressure at temperature $T_2$

$\Delta H_{vap}$ = Enthalpy of vaporization

R = Gas constant = 8.314 J/mol K

1) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

$T_1$ = initial temperature =363 K

$T_2$ = final temperature =373 K

$P_2=1 atm, P_1=?$

Putting values in above equation, we get:

$\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]$

$P_1=0.69671 atm \approx 0.6970 atm$

The vapor pressure at temperature 363 K is 0.6970 atm

2) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

$T_1$ = initial temperature =373 K

$T_2$ = final temperature =383 K

$P_1=1 atm, P_2?$

Putting values in above equation, we get:

$\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]$

$P_2=1.4084 atm \approx 1.410 atm$

The vapor pressure at 383 K is 1.410 atm

8 0

3 years ago

the combustion of a sample butane, C4H10 (lighter fluid) produced 2.46 grams of water. how many moles of water formed

enyata [817]

$2C_4H_{10}+13O_2$ ⇒ $8CO_2 + 10H_2O$

$n= \frac{m}{M} = \frac{m}{2M(H)+M(O)}= \frac{2,46}{2*1,0+16,0} = 0,14mol$

So 0,14mol are formed.

6 0

3 years ago

What are transferred in an oxidation-reduction reaction (1 point)?

madreJ [45]

electrons are transferred in a oxidation-reduction reaction

oxidation reduction chemical equation involve electrons transfer between two species. In this reduction-oxidation type of chemical equation oxidation number of molecule, atoms or ion changes by gaining or losing electrons,that is there an oxidizing agent and a reducing agent in the reaction.

7 0

3 years ago

Is Newton's statement a law or a theory? It is a theory because it developed and changed over time as new technology provided ne

nika2105 [10]

Answer:

It is a law because it is a statement of fact that does not need any more experimental support.

Explanation:

A hypothesis is an acceptable assumption that is formulated through the collection of information and data and that attempts to explain some phenomenon. In other words, a hypothesis is a conjecture with which one tries to explain an observed fact. The formulation of a hypothesis can be derived in two different ways: by generalization, from a certain number of cases or observed phenomena; and, by analogies observed in the occurrence of different phenomena.

A theory is something that attempts to explain some phenomenon and that is accepted as true by the scientific community. In other words, a theory is a set of rules that describe the behavior of a particular system.

A law is a statement that expresses the constant relationships between phenomena of nature, society or the mind. Scientific law can be defined as an invariable relationship of terms. In other words, a law is what is scientifically proven to be true, it is universally applicable.

So scientific theories and scientific laws are based on hypotheses. But a theory is the explanation of an observed phenomenon, while a scientific law is the description of an observed phenomenon.

The movements of bodies in space are governed by Newton's Laws. These are laws why they are demonstrated by mathematical formulas and Universal application.

Then, the correct option is <u><em>"It is a law because it is a statement of fact that does not need any more experimental support."</em></u>

5 0

3 years ago

Order the following from smallest to largest

Dmitry [639]

1. Quark

2. Electron

3. Proton and Neutron

4. Nucleus

5. Atom

6. Molecule

8 0

3 years ago