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2 years ago

What is the volume of the following rectangular prism?

Mathematics

1 answer:

nika2105 [10]2 years ago

6 0

Answer:

44/3

Step-by-step explanation:

V=L*W*H

WH=22/3

V=2*(22/3)

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Cal

saw5 [17]

$\text{Find how much Zelda paid for the visit to the ER:}\\\\\text{We know that her insurance pay's 85\% of the emergency room cost,}\\\text{ so multiply 0.85 from 4089 and subtract}\\\\4089*0.85=3,475.65\\\\4089-3,475.65=613.35\\\\\text{She pays \$613.35 of the emergency room cost}\\\\\text{We're not done yet, we also know she pays a \$100 deductible,}\\\\\text{So add 100 to 613.35}\\\\613.35+100 = 713.35\\\\\boxed{\text{She pays \$713.35}}$

8 0

3 years ago

On the first day it was posted online, a music video got 510 views. The number of views that the video got each day increased by

8090 [49]

Answer:

19,552 views on day 20, 114,763 views cumulative total for 20 days.

Step-by-step explanation:

The decimal equivalent to "increased by 20% per day" would be (510)*(1.20)/day, if we started with 510 views as day 0. Day 1 would be (510)*(1.20) = 612 views.

If we have n successively days, the equation would read (510)(1.20)^n.

This means that after, lets say, 3 days, the calculation would be (510)*(1.20)^3, or 881 views.

On day 20, the calculation is (510)*(1.2)^20, or 19,552 views.

But the question asks "How many total views did the video get over the course of the first 20 days . . ?" This seems to be asking the sum of the first 20 days, which is easy if you use a spreadsheet. But if you read the question to mean what are the total views on day 20, the answer would be 19,552 views.

If you read the question as asking for the total sum of views over 30 days, the answer is 114,763. Quick: what does that amount to at $0.05 per view.

3 0

2 years ago

The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell

emmasim [6.3K]

Answer:

Highest (-3,-3)

Lowest (2,2)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

$\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12$

completing the squares:

$\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2$

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of

$\bf f(x,y)=x^2+y^2$

subject to the constraint

$\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0$

Now we have

$\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)$

Let $\bf \lambda$ be the Lagrange multiplier.

The maximum and minimum must occur at points where

$\bf \nabla f=\lambda\nabla g$

that is,

$\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)$

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

$\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y$

Replacing in the constraint

$\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2$

from this we get

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0

3 years ago

I'm in algebra 1 please help i'm lost

german

The answer is #3... 2 and -6! Hope this helped!

5 0

3 years ago

Can someone Help me please

Sonbull [250]

Answer:

Lower quartile= 4

Middle quartile= 6

Upper quartile=8

7 0

3 years ago