Question

Find the missing lengths please help for a grade

Answer 1

Answer:

The answer is

$x = 10 \sqrt{3} \\ y = 5 \sqrt{3}$

Step-by-step explanation:

$\sin(60) = \frac{15}{x} \\ x= \frac{15}{ \sin(60) } = 10 \sqrt{3} \\ \sin(30) = \frac{y}{10 \sqrt{3} } \\ y = 10 \sqrt{3} \sin(30) \\ y = 10 \sqrt{3} \times .5 \\ y = 5 \sqrt{3}$

Answer 2

To find y use tangent
To find X use sine

15xtan30=y

15xsin30=x