Answer:
4. 1; 6; 2 — synthesis
Explanation:
<u>Decomposition reaction </u>is defined as the reaction in which a single large substance breaks down into two or more smaller substances.

<u>Single displacement </u>reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

<u>Synthesis reaction</u> is defined as the reaction in which smaller substances combine in their elemental state to form a larger substance.

The unbalanced combustion reaction is shown below as:-
On the left hand side,
There are 4 phosphorus atoms and 1 calcium atom
On the right hand side,
There are 2 phosphorus atoms and 3 calcium atoms
Thus,
Right side,
must be multiplied by 2 to balance phosphorus.
Left side,
is multiplied by 6 so to balance the whole reaction.
Thus, the balanced reaction is:-
Thus, answer:- 4. 1; 6; 2 — synthesis
Answer:
Neither side is favored
Explanation:
In a reaction at equilibrium in which reactants and products are gases, pressure is a factor that produces a shift of the equilibrium position. When the pressure is increased, the equilibrium is shifted to the side of the reaction with a fewer moles. In this reaction:
2 HD(g) ⇀↽ H₂(g) + D₂(g)
There is the same number of moles on both sides:
reactants side: 2 moles HD
products side: 1 mol H₂ + 1 mol D₂ = 2 moles
Therefore, the equilibrium position will not change.
Iodine value is a measure of the degree of unsaturation in fats and oils. It is essentially the number of grams of iodine consumed by 100 g of fat. If the iodine number is in the range of 0-70 then it is a fat, any value above 70 is considered an oil.
Formula:
Iodine number = (ml of 0.1 N Thiosulphate blank- ml of 0.1N thiosulphate test) * 12.7 *100/1000* wt of sample
vol of thiosulphate required to titrate test sample (given oil) = 1 ml
wt of sample = 0.2 g
Information on the volume of thiosulphate required to titrate the blank solution is essential for calculation.
Iodine number = (X-1.0) * 12.7 * 100/1000* 0.2 = (X-1.0)*6.35
I think it’s the last one
I think the right answer would be its particles have the most astounding normal dynamic vitality. Gas particles have a tendency to have the most astounding active vitality among the conditions of matter. They move in arbitrary movement. Trust this answers the question. Have a decent day.