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BabaBlast [244]
3 years ago
5

-4(4-x)=4/5(x+16) I need help

Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

x=9

Step-by-step explanation:

−4(4−x)=4/5(x+16)

(−4)(4)+(−4)(−x)=(4/5)(x)+(4/5)(16)(Distribute)

−16+4x=4/5x+64/5

4x−16=4/5x+64/5

4x−16−4/5x=4/5x+64/5−4/5x

16/5x−16=64/5

16/5x−16+16=64/5+16

16/5x=144/5

(5/16)*(16/5x)=(5/16)*(144/5)

x=9

hopfully this helps answer: x=9

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a. The water in the second tank decreases at a faster rate than the water in the first tank. The initial water level in the first tank is greater than the initial water level in the second tank.

Step-by-step explanation:

Step 1:

It is given that the time remaining in first tank is given by the equation y = -10x + 80. We can get the total water in the tank by substituting x = 0 in the equation. The total volume of water in first tank is 80 litres.

Step 2:

The value of y in the equation y = -10x + 80 will be 0 when the tank is fully empty. When y = 0 , 10x = 80, so x = 8. We can conclude that the first tank empties fully in 8 minutes.

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As per the given table for the second tank, 60 litres of water remains when x =0. So the total volume of water in the second tank = 60 litres.

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As per the given table for the second tank, the volume becomes 0 in 5 minutes. In 5 minutes 60 litres of water is emptied from second tank. So the water in  second tank decreases at rate of 60 / 5 = 12 litres per minute.

Step 5:

The initial volume of water in first tank is higher. The water in  second tank decreases at a faster rate than the first tank.

Step 6:

The only correct option is:

a. The water in  second tank decreases at a faster rate than the water in the first tank. The initial water level in  first tank is greater than the initial water level in the second tank.

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