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liq [111]
3 years ago
14

A dog can provide sufficient power to pull a sled with a 60 N force at a steady 2.0 m/s. Suppose the dog is hitched to a differe

nt sled that requires 120 N to move at a constant speed. How fast can the dog pull this second sled?
Physics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

v = 1.0 m/s

Explanation:

  • Applying the definition of power (rate of change of energy with respect to time), and the definition of average speed, we can say that the power is the product of the net force applied, times the speed achieved by the force on the mass of the object, as follows:
  • P = F* v
  • In this case, this power can be written as follows:
  • P = 60 N * 2.0 m/s = 120 J/s = 120 W
  • If the power remains constant, but now it is required a force of 120 N to move the sled at a constant speed, it is clear that the maximum speed possible will be 1.0 m/s, due to 120 N* 1.0 m/s = 120 W, which is the maximum power available.
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When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 0.120 m. The mass is now displ
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Answer:

Time period of the oscillation will be 0.695 sec

Explanation:

We have given mass attached to the string m = 0.350 kg

The spring is stretched by 0.120 m

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We know that force is given by F = Kx

So mg = kx

0.350\times 9.8=k\times 0.120

k = 28.5833

Now time period is given by

T=2\pi \sqrt{\frac{m}{k}}=2\times 3.14\sqrt{\frac{0.35}{28.5833}}=0.695sec

So time period of the oscillation will be 0.695 sec

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