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PtichkaEL [24]
2 years ago
13

give the mathematical expression for coulombs force if q1,q2 are the magnitude of charges and r is the distance between them.

Physics
1 answer:
Afina-wow [57]2 years ago
7 0

Give the mathematical expression for coulomb's force if q1, q2 are the magnitude of charges and r is the distance between them.

F=K q1q2/r2

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Suppose you have two identical capacitors. You connect the first capacitor to a battery that has a voltage of 21.2 volts, and yo
HACTEHA [7]

Answer:

r=2.743

Explanation:

The energy stored on a capacitor is of type potencial, therfore depends on the capacity to "store" energy. Inthe case of the capacitor, it stores charge (Q), and the equations you use to calculate it are:

E_p=\frac{Q^2}{2C}=\frac{QV}{2}=\frac{CV^2}{2}

In this case we know V and C, therefore we use the last expression:

E_{p1}=\frac{CV_1^2}{2}

E_{p2}=\frac{CV_2^2}{2}

\frac{E_{p1}}{E_{p2}}=r=\frac{\frac{CV_1^2}{2}}{\frac{CV_2^2}{2}}  \\r=(\frac{V_1}{V_2})^2\\r=(\frac{21.2}{12.8})^2

r=2.743

3 0
3 years ago
A 60 w (120 v) night light is turned on for an average 12 h a day year round. part a what is the annual cost of electricity at a
Zinaida [17]

The annual cost of electricity is $28.908 .

work done is equal to energy consumed

therefore total energy is calculated as power times the duration of operation .

W=P.t

where W= work done

            P=power

            t= time of operation

therefore,

total work done (W)=0.06×12×365 kw

=262.8 kw

so total annual electricity bill = 262.8×0.11

=$28.908

Learn more about electricity bill consumption here:

brainly.com/question/21116164

#SPJ4

4 0
1 year ago
useing newton's third law of motion explain how the motion of an automobile changes when the road surface is slippery
storchak [24]
Refer to the diagrams shown below.

The normal reaction of the road on the automobile is equal to the weight of the automobile (Newtons 3rd Law).
That is,
N = mg   (g = 9.8 m/s²)

When the road surface is dry, the resisting frictional force at the wheel is
F₁ = μ₁N
where
μ₁ =  the kinetic coefficient of friction.
The value of μ₁ is about 0.7 - 0.9 on a dry road.

When the road is wet, the resisting frictional force is
F = μ₂N
where
μ₂ =  the kinetic coefficient of friction on a wet road.
The value of μ₂ is about 0.1 - 0.4 on a wet road.

Because μ₂ < μ₁, the automobile tends to slip on a wet road, especially if the tires are worn.

3 0
4 years ago
A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu
zlopas [31]

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

4 0
4 years ago
A 10.3 kg block of ice slides without friction down a long track. The start of the track is 4.2 m higher than the end of the tra
Agata [3.3K]
Hello

1) Since there is no friction between the ice and the track, there is no loss of energy in the motion, so we can apply the law of conservation of energy.
The total energy E (sum of potential energy P and kinetic energy K) must be conserved:
E=P+K  

2) At the beginning of the motion, the total energy of the object is just potential energy:
E_1=P=mgh 
where m is the mass, g=9.81~m/s^2 is the gravitational acceleration, and h=4.2~m is the initial height of the body.

3) At the end of the motion, this potential energy has converted into kinetic energy, and so the total energy at this point is 
E_2= \frac{1}{2}mv^2
where m is the mass and v is the final velocity of the object.

4) We said that the total energy must be conserved, therefore we can write
E_1 = E_2
and so:
mgh= \frac{1}{2}mv^2
from which we can find v, the velocity:
v= \sqrt{2gh}= \sqrt{2\cdot9.81~m/s^2 \cdot 4.2~m}=9.08~m/s
8 0
4 years ago
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