Answer:
r=2.743
Explanation:
The energy stored on a capacitor is of type potencial, therfore depends on the capacity to "store" energy. Inthe case of the capacitor, it stores charge (Q), and the equations you use to calculate it are:

In this case we know V and C, therefore we use the last expression:



r=2.743
The annual cost of electricity is $28.908 .
work done is equal to energy consumed
therefore total energy is calculated as power times the duration of operation .

where W= work done
P=power
t= time of operation
therefore,
total work done (W)=0.06×12×365 kw
=262.8 kw
so total annual electricity bill = 262.8×0.11
=$28.908
Learn more about electricity bill consumption here:
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Refer to the diagrams shown below.
The normal reaction of the road on the automobile is equal to the weight of the automobile (Newtons 3rd Law).
That is,
N = mg (g = 9.8 m/s²)
When the road surface is dry, the resisting frictional force at the wheel is
F₁ = μ₁N
where
μ₁ = the kinetic coefficient of friction.
The value of μ₁ is about 0.7 - 0.9 on a dry road.
When the road is wet, the resisting frictional force is
F = μ₂N
where
μ₂ = the kinetic coefficient of friction on a wet road.
The value of μ₂ is about 0.1 - 0.4 on a wet road.
Because μ₂ < μ₁, the automobile tends to slip on a wet road, especially if the tires are worn.
Answer:
t = 0.657 s
Explanation:
First, let's use the appropiate equations to solve this:
V = √T/u
This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.
Where:
V: Speed of the disturbance
T: Tension of the rope
u: linear density of the rope.
The density of the rope can be calculated using the following expression:
u = M/L
Where:
M: mass of the rope
L: Length of the rope.
We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:
u = 2.31 / 10.4 = 0.222 kg/m
Now, replacing in the first equation:
V = √55.7/0.222 = √250.9
V = 15.84 m/s
Finally the time can be calculated with the following expression:
V = L/t ----> t = L/V
Replacing:
t = 10.4 / 15.84
t = 0.657 s
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1) Since there is no friction between the ice and the track, there is no loss of energy in the motion, so we can apply the law of conservation of energy.
The total energy E (sum of potential energy P and kinetic energy K) must be conserved:
2) At the beginning of the motion, the total energy of the object is just potential energy:
where m is the mass,

is the gravitational acceleration, and

is the initial height of the body.
3) At the end of the motion, this potential energy has converted into kinetic energy, and so the total energy at this point is

where m is the mass and v is the final velocity of the object.
4) We said that the total energy must be conserved, therefore we can write

and so:

from which we can find v, the velocity: