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Rainbow [258]
3 years ago
13

Q5. Make t the subject of the formula t +1 m = t-3 can someone help please

Mathematics
1 answer:
Mrac [35]3 years ago
8 0
Answer: (3m+1)/(m-1)

Working out in picture


Hope this helps!

You might be interested in
Un futbolista ha metido 2/9 del número de goles marcados por su equipo y otro la
storchak [24]

Answer:

77 goles

Step-by-step explanation:

Un futbolista ha marcado 2/9 del número de goles marcados por su equipo.

Otro anotó una cuarta parte del resto.

El resto = 1 - 2/9

= 7/9

De ahí que otro futbolista anotó

= 1/4 de 7/9

= 7/36

Si los otros jugadores han marcado 45 goles

Tenemos que averiguar la fracción de goles que marcó el otro jugador

Deje que el número total de goles marcados por el equipo durante la temporada = 1

Por lo tanto:

1 - (2/9 + 7/36)

1 - (8 + 7/36)

1 - 15/36

1 - 5/12

= 7/12

¿Cuántos goles marcó el equipo a lo largo de la temporada?

El número total de goles que marcó ese equipo se calcula como:

7/12 × x = 45

Donde x = número total de goles

7x / 12 = 45

Cruz multiplicar

7x = 45 × 12

x = 45 × 12/7

x = 77,142857143

Aproximadamente = 77 goles

7 0
2 years ago
How many inches are in 43 yards
tekilochka [14]

Answer: 1548

Explanation: 1 yd = 36 inches, so all you have to do is multiply 43 by 36 and you get your answer.


6 0
3 years ago
Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0
3 years ago
Please help with this &amp; show your working out to get brainliest. And please don’t trick me.
timurjin [86]
The lowest is the square root of 9 which is 3. After that is 3.15, 13/4 (3.25), 3 1/2 (3.50). My explanation would be: first I found out the square root of 9. Then divided 13 by 4.
7 0
3 years ago
If 3x - 6y = 8, then x - 2y =
Fiesta28 [93]

Answer:

8/3 or 2.6666

Step-by-step explanation:

You have divided the first equation by 3 -- all except the 8. So you must divide the 8 by 3 giving you 8/3 which is 2 2/3 or 2.66666

Answer (x - 2y) = 8/3

8 0
3 years ago
Read 2 more answers
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