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IceJOKER [234]
3 years ago
14

Two linear functions are represented in different formats. Function 1: x y 0 5 2 ​11​ 5 ​20​ 8 ​29​ Function 2: Graph of a line

passing through the point begin ordered pair 0 comma negative 1 end ordered pair and the point begin ordered pair 2 comma 0 end ordered pair. Which statements are true? Select each correct answer. Function 1 has a greater rate of change than function 2. Function 2 has a greater rate of change than function 1. Function 1 has a greater y-intercept than function 2. Function 2 has a greater y-intercept than function 1.
Mathematics
1 answer:
sukhopar [10]3 years ago
3 0

Answer:

2 is it I think it’s hard

Step-by-step explanation:

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Your friend says she used a common
AfilCa [17]

Step-by-step explanation:

An equivalent fraction can be found by either multiplying the numerator and denominator by the same number or dividing the numerator and the denominator by the same number.

7 0
3 years ago
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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
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Find the missing exponent. Set up an equation and solve. : x^4·x^n = x^5
Assoli18 [71]
Use\ a^n\cdot a^m=a^{n+m}\\\\x^4\cdot x^n=x^5\\\\x^{4+n}=x^5\iff4+n=5\ \ \ |subtract\ 4\ from\ both\ sides\\\\\boxed{n=1}
7 0
3 years ago
John kept track of how many baskets were made in a basketball game. After 4 minutes, 5 baskets were made.
ivann1987 [24]

1 basket is between 9 and 10 minutes .

<u>Step-by-step explanation:</u>

Here we have , John kept track of how many baskets were made in a basketball game. After 4 minutes, 5 baskets were made.  We need to find How many baskets were made between 9 and 10 minutes . Let's find out:

In order to calculate baskets between 9 min and 10 min we will find baskets at 10 min and at at 9 min , will subtract than !

Baskets at 10 min :

At 4 min we have 5 baskets so , in 10 min

⇒ (10)\frac{5}{4}

⇒ 1.25(10)

⇒ 12.5

Baskets at 9 min :

At 4 min we have 5 baskets so , in 9 min

⇒ (9)\frac{5}{4}

⇒ 1.25(9)

⇒ 11.25

So , Baskets between 10 & 9 min is 12.5-11.25=1.25 , which on rounding off gives 1 . Therefore , 1 basket is between 9 and 10 minutes .

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Evaluate the expression for x = 3.4, x = 7.6
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u have to multiply both of the numbers

3 0
3 years ago
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