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andrew11 [14]
2 years ago
5

CAN SOMEONE PLZZZ HELP ME???

Mathematics
1 answer:
ioda2 years ago
7 0
Yes, what’s your question?
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crimeas [40]
A scalene triangle..
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A cube. The top face has points G, B, C, F and the bottom face has points H, A, D, E.
Triss [41]

Answer:

its side CE

Step-by-step explanation:

I got it wrong and it showed me the answer. Hope this helps!

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3 years ago
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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
3 + root 3 *2 +root 2​
icang [17]

Answer:

6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Given

(3 + \sqrt{3} )(2 + \sqrt{2} )

Each term in the second factor is multiplied by each term in the first factor, that is

3(2 + \sqrt{2} ) + \sqrt{3} (2 + \sqrt{2} ) ← distribute both parenthesis

= 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}

4 0
3 years ago
15 is 0.4% of what number?
zavuch27 [327]
 0.4 is 100% - because it's the output value of the task. <span>If 0.4 is 100%, so wyou can write it down as 0.4=100%. </span><span>We know, that x is 15% of the output value, so we can write it down as x=15%. so your anser is 15</span>
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3 years ago
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