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Dahasolnce [82]
2 years ago
12

A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4

.0 m/s2. What is the final velocity of the roller coaster? Round your answer to the nearest whole number.
m/s
Physics
1 answer:
Vera_Pavlovna [14]2 years ago
8 0

Answer:

2as = v² - u²

v = √(2as + u²)

v = √(2 x 4 x 400 + 13²)

v = 58 m/s

Explanation:

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A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function
Sunny_sXe [5.5K]

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

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To get the position equation we just need to integrate the above equation:

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Replacing that in our integral we get:

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Now we remember that $u=\cos (\omega t)$

Then we have:

$f(t)=\frac{\cos ^3(\omega t)}{3}+C

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Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

To learn more about motion equations, refer to:

brainly.com/question/19365526

#SPJ4

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