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Allushta [10]
3 years ago
8

Suppose you wind a wire with a current into a coil. How have you changed the wire’s magnetic field?

Physics
1 answer:
ss7ja [257]3 years ago
5 0

Answer:

Magnetic field strength increases

Explanation:

Winding of wire with current is one of the ways used to increase magnetic field. When the wires are closely wound and current increases, the magnetic strength also increases since the magnetic strength is directly proportional to the number of wire windings. Moreover, increasing the current also enhances the magnetic field strength.

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A long electric cable is suspended above the earth and carries a current of 345 A parallel to the surface of the earth. The eart
jok3333 [9.3K]

Answer:

0.906 N

Explanation:

Formula for magnetic force acting on current carrying cable:

F = IBLsin(\theta)

Where I = 345A is the current in the wire, B = 5.6*10^{-5} T is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. \theta = 88.2^o is the angle between vector B and cable direction.

F = 345*5.6*10^{-5}*46.9*sin(88.2^o)

F = 0.906 N

7 0
3 years ago
Cientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below.
scZoUnD [109]

Answer:

A few of the positive particles aimed at a gold foil seemed to bounce back.

Explanation:

3 0
2 years ago
Which formula is used to find an object's acceleration?
irga5000 [103]
Acceleration= change in velocity/time
8 0
2 years ago
Read 2 more answers
Một chất điểm chuyển động trong mặt phẳng Oxy với phương trình :<br> { = 2 + 10
In-s [12.5K]

Answer:

plz write your questions in English

3 0
2 years ago
A load of 800 N is lifted using a block and tackle having 5 pulleys. If the applied effort is 200 N, calculate
ser-zykov [4K]

Explanation:

Load=800N

Effort=200N

1. Mechanical Advantage = LOAD/EFFORT

= 800N/200N

= 4

2 Velocity Ratio = no. Of pulleys =5

3. Efficiency = Mechanical advantage / velocity ratio × 100%

= (4/5)×100%

=80%

4. output work= load×load distance

= 800N × 5m

= 4 × 1000J

5. Efficiency = (output work/input work) ×100%

Or, 80% = (4000J/input work) ×100%

Or, 80%/100% = 4000J/inputwork

Or, 4/5 = 4000J/inputwork

Or, input work =4000J × 5/4

Input work = 5×1000J

I hope it helped! ;-)

8 0
2 years ago
Read 2 more answers
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