It should be 3.39 when u multiply 2.26 from 1.5 it gone give u 3.39 it be better if u learn the triangle
<span>The scales is 1 m = 10 dm = 100 cm = 1000 mm. Then 10 dm equals 1000 mm and 1 dm equals 100 mm.The names of the measures in that scale are meter, decimeter, centimeter and milimiter. So, the answer is that the length that is 100 times larger than a milimieter is the decimeter (dm). </span>
Explanation:
Given that,
Frequency in the string, f = 110 Hz
Tension, T = 602 N
Tension, T' = 564 N
We know that frequency in a string is given by :
, T is the tension in the string
i.e.
, f' is the another frequency


f' =106.47 Hz
We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :



So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.
Answer:
36 Ω
Explanation:
Since the 3 resistors are connected in parallel.
The combined resistance of the resistor is
1/Rc = 1/R + 1/R + 1/R ...................... Equation 1
Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor
Rc = R/3 ....................... Equation 2
The formula of power is given as
P = V²/Rc
Rc = V²/P ................ Equation 3
Where V = Voltage, R = Combined Resistance, P = power.
Given: V = 48 V, 192 W.
Substitute into equation 3
Rc = 48²/192
Rc = 12 Ω
From equation 2
Rc = R/3
R = 3Rc
Where Rc = 12 Ω
R = 3×12
R = 36 Ω
Hence the resistance on each resistor = 36 Ω
Answer:
–50.96
Explanation:
The following data were obtained from the question:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =
a = (Vբ – Vᵢ) / t
With the above formula, we can determine how fast the object is traveling after 5 s as follow:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
a = (Vբ – Vᵢ) / t
– 9.8 = (Vբ – 0) / 5.2
– 9.8 = Vբ / 5.2
Cross multiply
Vբ = –9.8 × 5.2
Vբ = –50.96 m/s
Therefore, the object is traveling at
–50.96 m/s