The mass of water that is in 150 g of Mgso4.7H20 is calculated as follows
mass of water= molar mass of H20 in MgSO4.7H20 /total molar mass of MgSO4.7H20 x mass ( 150g)
molar mass of h20 = 18 x 7= 126 g/mol since there is 7 water molecules
molar mass of MgSO4.7H20= 24 + 32 + (16x4) + (18x7) = 246g/mol
Mass of water is therefore= 126 g/mol/246g/mol x150g =76.8 g
Answer:
B.111
Explanation:
Atomic mass = number of protons(or atomic number) + number of neutrons
186 = 75 + number of neutrons
number of neutrons = 186 -75 = 111
Answer:
Hello! Your answer would be, D) HCI
Explanation:
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Answer:
1) P4O10 + 6H20 → 4H3PO4
2) 1.25 moles of P4O10
3) 7.5 moles of water
Explanation:
1. Write the balanced equation for this reaction
P4O10 + 6H20 → 4H3PO4
2) Determine the number of moles of P4O10 required to produce 5.00 moles of phosphoric acid.
For 1 mole P4O10 consumed, we need 6 moles of water to produce 4 moles of H3PO4
If we get 5.00 moles of H3PO4, we'll have 5/4 = 1.25 moles of P4O10 consumed.
3) Determine the number of moles of water required to produce 5.00 moles of phosphoric acid
For 1 mole P4O10 consumed, we need 6 moles of water to produce 4 moles of H3PO4
If we have 5.00 moles of H3PO4, we'll get (6/4)*5 = 7.5 moles of water consumed.