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Dmitrij [34]
3 years ago
14

Someone pleaseeeeee helppp

Chemistry
1 answer:
Ede4ka [16]3 years ago
8 0

i think it's the last answer!

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Calculate the amount of nacl needed to prepare 50 ml of 0.9% nacl solution and 20% nacl solution
Westkost [7]
Your answer would be, 
Formula: Molarity (M) = Number of moles of solute/Solutions volume Liters

0.009(50) = .45 gm dissolved in 50 ml H2o
= 0.20(50) = 10 gm





Hope that helps!!!
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1. distance = 10 m<br> time = 2 s<br> What is this object's speed?
faust18 [17]
Speed = distance/time
10m/2s = 5m/s
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Which statement is true for nuclear reactions but not for chemical reactions?
IrinaVladis [17]

Answer:maybe C

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What is the mass in grams of 1.00 x 10 24 atoms of Mn?
Alex17521 [72]
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0
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What happens to an electron during an electron transition?
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I think the answer is d not real fir sure I'll find out in the morning sorry
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