Answer:
Step 1
Because the number in front of the bracket is 1 and it is also affected by the negative sign(-),5 is supposed to be negative not positive because (negative by positive is negative)
And since the first step has an error in it,the remaining steps would also be wrong.
Using distance between two points to find the lengths of the edges of the triangle, the correct option is:
b. Isosceles
The distance between two points,
and
, is given by:
![d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D)
Vertex D is translated 4 units to the right is (9,8).
The lengths of the edges are:
![DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}](https://tex.z-dn.net/?f=DN%20%3D%20%5Csqrt%7B%289%20-%20%28-3%29%29%5E2%20%2B%20%288%20-%2010%29%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%20%2B%202%5E2%7D%20%3D%20%5Csqrt%7B148%7D)
![DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}](https://tex.z-dn.net/?f=DO%20%3D%20%5Csqrt%7B%289%20-%20%28-3%29%29%5E2%20%2B%20%288%20-%206%29%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%20%2B%202%5E2%7D%20%3D%20%5Csqrt%7B148%7D)
![NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4](https://tex.z-dn.net/?f=NO%20%3D%20%5Csqrt%7B%28-3%20-%20%28-3%29%29%5E2%20%2B%20%2810%20-%206%29%5E2%7D%20%3D%20%5Csqrt%7B0%5E2%20%2B%204%5E2%7D%20%3D%204)
<u>Two edges of the same length</u>, hence, it is an isosceles triangle, given by option b.
You can learn more about distance between two points at brainly.com/question/18345417
Answer:
5/6
Step-by-step explanation:
Answer:
y= - frac4/7 x + frac9/7
Step-by-step explanation:
Answer:
the solution to the system is (1,3)
Step-by-step explanation:
x = 1 , y = 3