Answer:
Option B
x ≥ (-5)
Step-by-step explanation:
<h3>
<u>Given</u>;</h3>
So,
-3(x + 4) ≥ x + 8
-3x – 12 ≥ x + 8
Add both sides 12 we get,
-3x – 12 + 12 ≥ x + 8 + 12
-3x ≥ x + 20
Similarly, subtract x from both sides we get,
-3x – x ≥ x – x + 20
-4x ≥ 20
Then, divide both sides by (-4) we get,
-4x/(-4) ≥ 20/(-4)
x ≥ -5
Thus, The answer is x ≥ (-5).
Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is
Where, 
is the point on the plane and 
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is
Therefore, the equation of the plane is .
Answer:
y=3x-7
Step-by-step explanation:
lines are parallel hence gradient from the equation in question is the same as the gradient of the equation to be found.. comparing to y=mx+c, eq in question has grad 3... from the formula y-y1=m(x-x1) where (x1,y1) is equal to the point in question
Answer:
27/1000
Step-by-step explanation:
P(G,G,G) = 3/10 x 3/10 x 3/10
The answer should be A. 4.5
Because line x is just over half of the length of the line that is 8ft
