Answer:
Fundamental properties of atoms including atomic number and atomic mass. The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons.
Explanation:
Fundamental properties of atoms including atomic number and atomic mass. The atomic number is the number of protons in an atom, and isotopes have the same atomic number but differ in the number of neutrons.
The diatomic molecule H2 has an extremely low boiling point because only weak Vander waals forces are present between the atoms of hydrogen molecule. This weak inter-molecular forces are easily broken when heat is apply resulting in low boiling point.
Answer:
The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point
Explanation:
To solve the above question we have the given variable as follows
ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole
However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.
The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles
Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ
Answer:
The third one
Explanation:
Nickel-62 has the highest binding energy per nucleon of any isotope for any element. Isotopes heavier than 62Ni cannot be formed by nuclear fusion without losing energy.
Answer:
The new pressure in the balloon is 16.3 atm
Explanation:
Gay-Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant.
This law establishes that pressure and temperature are directly proportional quantities, that is to say that if the temperature increases the pressure increases and if the temperature decreases the pressure decreases.
Mathematically, Gay-Lussac's law states that, when a gas undergoes a constant volume transformation, the quotient of the pressure exerted by the gas temperature remains constant:
When you want to study two different states, an initial one and a final one, of a gas, you can use the expression:
In this case:
- P1= 14.7 atm
- T1= 273 K
- P2= ?
- T2= 303 K
Replacing:
Solving:
P2= 16.3 atm
<u><em>The new pressure in the balloon is 16.3 atm</em></u>
