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BaLLatris [955]

2 years ago

15

Plan an investigation to explore the relationship between properties of substances and the electrical forces within those substa

nces.

1 answer:

kenny6666 [7]2 years ago

8 0

Answer:

la verdad no se no ablo ingles solo espanis

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The chemical formula for rubies is AI2O3 list the elements that combine to form a ruby and the number of atoms of each element i

max2010maxim [7]

Since the chemical formula is Al2O3, it means in a single molecule there are 2 atoms Al and 3 atoms O. O means oxygen and Al means alluminium, so there are 2 atoms alluminium and 3 atoms oxygen.

5 0

3 years ago

Explain, in your own words, what volumic mass is

ira [324]

Answer:

The density (more precisely, the volumetric mass density; also known as specific mass), of a substance is its mass per unit volume. The symbol most often used for density is ρ (the lower case Greek letter rho), although the Latin letter D can also be used.

5 0

2 years ago

An I.V. infusion order is received for Lidocaine 2 g in 250 ml of 0.9% NaCl to be infused at 3 mg/min. What will the flow rate b

Tamiku [17]

Answer:

The flow rate would be 22.5ml/hr

Explanation:

Volumetric flow rate = Mass flow rate ÷ density

Mass flow rate = 3mg/min = 3mg/min × 60min/1hr = 180mg/hr

Density = mass/volume = 2g/250ml = 0.008g/ml = 0.008g/ml × 1000mg/1g = 8mg/ml

Volumetric flow rate = 180mg/hr ÷ 8mg/ml = 22.5ml/hr

5 0

3 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

Darya [45]

Answer:

0.382g

Explanation:

Step 1: Write the reduction half-reaction

Al³⁺(aq) + 3 e⁻ ⇒ Al(s)

Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s

We will use the following relationships.

1 A = 1 C/s

1 mole of electrons has a charge of 96486 C (Faraday's constant)

1 mole of Al is produced when 3 moles of electrons pass through the cell.

The molar mass of Al is 26.98 g/mol.

The mass of Al produced is:

$41.0s \times \frac{100C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molAl}{3mole^{-} } \times \frac{26.98gAl}{1molAl} = 0.382gAl$

7 0

3 years ago

A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid

const2013 [10]

The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

<u>Answer:</u> The pH of the solution is 10.09

<u>Explanation:</u>

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HClO$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL$

Putting values in above equation, we get:

$1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL$

At equivalence, the number of moles of acid is equal to the number of moles of base. Also, the moles of salt which is NaClO will also be the same.

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

<u>For HClO:</u>

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

$0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol$

<u>For NaClO:</u>

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

$\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M$

To calculate the pH of the solution, we use the equation:

$pH=7+\frac{1}{2}[pK_a+\log C]$

where,

$pK_a$ = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

$pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09$

Hence, the pH of the solution is 10.09

4 0

3 years ago